IBMOA #29
Get Max Occurrences
估计中等可在线判题
Find the maximum number of times a substring occurs in the original string; occurrences may overlap. Candidate lengths are between minLength and maxLength, and the number of distinct characters must not exceed maxUnique; output 0 if there is no valid candidate.
输入格式
The first line contains minLength maxLength maxUnique, and the second line contains the string. Original bounds: 2≤length≤100000, 2≤minLength≤maxLength≤26 and maxLength<string length, 2≤maxUnique≤26. The source does not restrict the character set; this site supports non-newline Unicode scalar characters, each character counts as one code point, and the total UTF-8 size is ≤400100 bytes.
输出格式
Output one integer, the answer.
样例 1
输入:
2 4 2
abcde
输出:
1
样例 2
输入:
2 3 2
ababab
输出:
3
样例 3
输入:
2 3 2
aaaa
输出:
3
样例说明
The examples give 1, 3 and 3 respectively; ab occurs 3 times in ababab, and occurrences of aa may overlap.