Goldman SachsOA #11
Lock Code
估计困难评测数据准备中,可先阅读题面
You are given an array of integers codeSequence of length n and an integer maxValue. A locking system allows you to modify any number in the array to any integer less than or equal to maxValue at a cost of 1 per change.
Two numbers are co-prime if their greatest common divisor (GCD) is 1. To unlock the repository, you need to select a number from the array that is co-prime with all other numbers in the array.
The lock's code is calculated as the maximum possible value of: selected number - total modification cost
Your task is to determine the lock code by selecting an optimal number from the array after modifications that is co-prime with all other numbers in the array.
Function Description
Complete the function decryptCodeLock in the editor with the following parameters:
int codeSequence[n]: the array presented by the code lockint maxValue: the maximum possible value for any element in the array Returnsint: the lock code
Constraints
- 1 ≤ n ≤ 10³
- 1 ≤ maxValue ≤ 10⁹
- 1 ≤ codeSequence[i] ≤ maxValue
Example 1
Input:
codeSequence = [3, 2, 4]
maxValue = 6
Output:
4
Explanation: Optimally:
- Change the element at the third position to 5 at the cost of 1 unit:
codeSequence'= [3, 2, 5]. - Choose the element 5 since it is co-prime with both 2 and 3.
- Calculate lock code = selected number - cost = 5 - 1 = 4. Return 4 as the answer.
Example 2
Input:
codeSequence = [1, 2, 3]
maxValue = 6
Output:
4
Explanation: Optimally, change the second and third elements to 5 and 6 at a cost of 2 units, resulting in [1, 5, 6]. The number 6 is coprime with both 1 and 5. The lock's code is 6 - 2 (cost) = 4.
Example 3
Input:
codeSequence = [2, 4, 6, 8]
maxValue = 8
Output:
6
Explanation: Optimally, change the third element to 7 at a cost of 1 unit, resulting in [2, 4, 7, 8]. The number 7 is coprime with 2, 4, and 8. The lock's code is 7 - 1 (cost) = 6.