Interview questions · DoorDash
Solve tree distance and design file system
This interview question evaluates algorithm design, data structures, correctness, complexity, edge cases, and implementation details in a realistic interview setting. A strong answer for Solve tree distance and design file system states assumptions, handles edge cases, explains trade-offs, and shows how to validate the result clearly.
Given a binary tree, find the maximum distance between two 'alive' nodes, where 'alive' nodes are initially the leaves; follow-up: allow the set of 'alive' nodes to be specified arbitrarily. LeetCode 1166. Design File System
https://leetcode.com/problems/design-file-system/description/
What a Strong Answer Covers
- A clear algorithm with the right data structures and enough pseudocode or code-level detail to implement it.
- A correctness argument that explains why the algorithm covers all required cases.
- Time and space complexity, plus at least one alternative approach when relevant.
- Focused tests for normal cases, edge cases, and failure modes.
Follow-up Questions
- How would the approach change if the input were streaming or too large for memory?
- What invariants would you assert in production code?
- Which tests would catch off-by-one, duplicate, or tie-breaking bugs?
Solution
Solution Alignment
The prompt asks for an implementation-level answer. The safest way to present it is to define the state, maintain clear invariants, then walk through complexity and tests.
Problem Restatement
Question Given a binary tree, find the maximum distance between two 'alive' nodes, where 'alive' nodes are initially the leaves; follow-up: allow the set of 'alive' nodes to be specified arbitrarily. LeetCode 1166. Design File System https://leetcode.com/problems/design-file-system/description/
Recommended Approach
Choose traversal based on the required output. DFS is natural for subtree computations, reconstruction, and range pruning; BFS is natural for level order or side views. Keep per-depth or per-position state when the output depends on columns, rows, or depths.
Correctness
The implementation should maintain an invariant after each loop or operation that directly matches the problem statement. At termination, that invariant implies the returned value has considered every valid candidate exactly once, or has preserved the required data-structure state after every API call.
Complexity
Most tree traversals are O(n) time and O(h) recursion stack for DFS or O(w) queue space for BFS, where h is height and w is maximum width.
Edge Cases and Tests
Empty tree, one node, skewed tree, duplicate values when reconstruction assumes uniqueness, deep recursion, and tie-breaking for same row/column nodes.
Community answers
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