Interview questions · DoorDash
Identify members lacking specialty coverage
Identify members lacking specialty coverage evaluates algorithm design, data structures, correctness, complexity, edge cases, and implementation details in a realistic interview setting. A strong answer states assumptions, handles edge cases, explains trade-offs, and shows how to validate the result clearly.
Oscar wants to ensure that every insurance member has adequate access to in-network healthcare providers within a reasonable travel distance.
You are given:
- A list of providers, where each provider has:
id: an integer provider IDspecialty: a string (e.g.,"Cardiology","Dermatology")location: a 2D coordinate(x, y)representing the provider’s location
- A list of members, where each member has:
id: an integer member IDlocation: a 2D coordinate(x, y)representing the member’s locationrequired_specialties: a list of strings indicating the specialties this member needs
- A number
max_distance(float or integer), which is the maximum allowed travel distance.
Assume Euclidean distance between two points (x1, y1) and (x2, y2):
A member has adequate coverage if, for every specialty in their required_specialties, there exists at least one provider with that specialty whose distance from the member is less than or equal to max_distance.
A member lacks adequate coverage if there is at least one required specialty for which no such provider exists within max_distance.
Task:
Write a function that, given providers, members, and max_distance, returns a list of the IDs of all members who lack adequate coverage.
You may return the member IDs in any order.
Example
providers = [
{"id": 1, "specialty": "Cardiology", "location": (1, 2)},
{"id": 2, "specialty": "Dermatology", "location": (3, 4)},
]
members = [
{"id": 101, "location": (2, 3), "required_specialties": ["Cardiology", "Dermatology"]},
{"id": 102, "location": (10, 10), "required_specialties": ["Cardiology"]},
]
max_distance = 5
Distances:
- Member 101 to provider 1 (Cardiology):
- distance = ≤ 5
- Member 101 to provider 2 (Dermatology):
- distance = ≤ 5
- Member 102 to provider 1 (Cardiology):
- distance = > 5
So member 101 has adequate coverage for all required specialties, but member 102 does not.
Expected output:
[102]
What a Strong Answer Covers
- A clear algorithm with the right data structures and enough pseudocode or code-level detail to implement it.
- A correctness argument that explains why the algorithm covers all required cases.
- Time and space complexity, plus at least one alternative approach when relevant.
- Focused tests for normal cases, edge cases, and failure modes.
Follow-up Questions
- How would the approach change if the input were streaming or too large for memory?
- What invariants would you assert in production code?
- Which tests would catch off-by-one, duplicate, or tie-breaking bugs?
Solution
Solution Alignment
The prompt asks for an implementation-level answer. The safest way to present it is to define the state, maintain clear invariants, then walk through complexity and tests.
Problem Restatement
Oscar wants to ensure that every insurance member has adequate access to in-network healthcare providers within a reasonable travel distance. You are given: - A list of providers, where each provider has: - id: an integer provider ID - specialty: a string (e.g., "Cardiology", "Dermatology") - location: a 2D coordinate (x, y) representing the provider’s location - A list of members, where each member has: - id: an integer member ID - location: a 2D coordinate (x, y) representing the member’s location - required_specialties: a list of strings indicating the specialties this member needs - A number max_distance (float or integer), which is the maximum allowed trave...
Recommended Approach
Use the string constraints to choose between two pointers, a stack, frequency counts, prefix/suffix state, or dynamic programming. Maintain the invariant that processed characters have already been normalized, counted, or matched according to the operation.
Correctness
The implementation should maintain an invariant after each loop or operation that directly matches the problem statement. At termination, that invariant implies the returned value has considered every valid candidate exactly once, or has preserved the required data-structure state after every API call.
Complexity
Most direct string scans are O(n) time. Space ranges from O(1) for two pointers to O(n) for stacks, maps, or DP tables.
Edge Cases and Tests
Empty string, length 1, repeated characters, invalid characters, case sensitivity, Unicode vs ASCII, and very long input.
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