cswork / libraryOpen practice workspace

Interview guides · Impetus

Impetus Software Engineer Interview Guide

Impetus Software Engineer interview guide: reported rounds, questions and how candidates describe the process.

The 60-second brief

As a Software Engineer at Impetus, you are at the heart of our mission to solve complex data engineering and digital transformation challenges for global enterprises. You will work on high-scale, high-impact projects that require a deep understanding of distributed systems, data processing, and cloud-native architectures. Your contributions will directly influence how our clients leverage their data to drive business intelligence and operational efficiency. This role is designed for engineers who thrive on technical rigor and intellectual curiosity. You will be expected to move beyond simple implementation, contributing to architectural decisions and optimizing performance in environments where scale is the norm.

This guide is scoped to a Software Engineer candidate at Impetus.

Focus areas

  • Data Structures & Algorithms (DSA)
  • Database Management Systems (DBMS)
  • Structured Query Language (SQL)

Where to focus your preparation

No round sequence has been reported for Impetus. Confirm the format with your recruiter.

Preparation focus

No round sequence has been reported for this company, so confirm the format with your recruiter and work the reported questions below.

What to demonstrate

  • Breadth across the topics this company reports testing
  • Whether you confirm the format before preparing for it

How to prepare

  • Ask the recruiter for the sequence, the duration of each stage and whether you will be writing code
  • Work the reported questions below and time yourself

Where candidates lose points

Think Aloud

Always verbalize your thought process while solving problems. This helps the interviewer understand your logic even if you get stuck.

Ask Clarifying Questions

Never jump straight into coding. Understand the constraints of the problem first.

Be Honest About Your Knowledge

If you don't know an answer, admit it, but explain how you would go about finding the answer.

Questions & practice

Explain the difference between process and thread in an Operating System.

Medium · Core Computer Science Fundamentals

Approach

  1. Say what the runtime actually does before reasoning about the code.
  2. Name what is shared across threads and what owns each piece of state.
  3. Identify the window where an invariant is briefly untrue.
  4. Distinguish a value from a reference to it, and say which one you handed out.

Follow-up

  • What happens if two callers reach this at the same time?
  • Where could this allocate more than you expect?

Given an array, how would you find the subarray with the largest sum?

Medium · Data Structures and Algorithms

Approach

  1. Restate the input: its shape, its size, and what is guaranteed about it.
  2. Name the brute-force solution and its complexity before improving on it.
  3. Choose the data structure from the access pattern, not from familiarity.
  4. State the target complexity and say which constraint rules the naive version out.

Follow-up

  • How does this change if the input no longer fits in memory?
  • What is the worst case, and how likely is it on real data?

How do you implement a queue using two stacks?

Medium · Data Structures and Algorithms

Approach

  1. Restate the input: its shape, its size, and what is guaranteed about it.
  2. Name the brute-force solution and its complexity before improving on it.
  3. Choose the data structure from the access pattern, not from familiarity.
  4. State the target complexity and say which constraint rules the naive version out.

Follow-up

  • How does this change if the input no longer fits in memory?
  • What is the worst case, and how likely is it on real data?

What are the different types of joins in SQL, and when would you use a Left Join versus an Inner Join?

Medium · Core Computer Science Fundamentals

Approach

  1. Name the grain you start from and join outward from it.
  2. Check whether any join is one-to-many before aggregating, or the sums inflate.
  3. Say which index the query would use, and what makes it unusable.
  4. Handle the rows that do not match: that is usually the actual question.

Follow-up

  • How does the query change if that join becomes one-to-many?
  • What happens to this when the table is ten times larger?

Explain the concept of normalization in DBMS and its impact on performance.

Medium · Core Computer Science Fundamentals

Approach

  1. Name the grain you start from and join outward from it.
  2. Check whether any join is one-to-many before aggregating, or the sums inflate.
  3. Say which index the query would use, and what makes it unusable.
  4. Handle the rows that do not match: that is usually the actual question.

Follow-up

  • How does the query change if that join becomes one-to-many?
  • What happens to this when the table is ten times larger?

What is the difference between TCP and UDP, and in what scenarios would you choose one over the other?

Medium · Core Computer Science Fundamentals

Approach

  1. Clarify what is being asked and what a complete answer contains.
  2. State your assumptions explicitly before working the problem.
  3. Say what you would check first and why it is the highest-information step.
  4. Work from the requirement backwards to the design.

Follow-up

  • What assumption would you test first?
  • How would you know your answer was wrong?

Shard by tenant when one tenant outgrows a single shard

Hard · sharding · hot partition · routing

One primary holds resource, resource_revision, outbox_event and idempotency_key for every tenant and is at its write ceiling at 1.2k writes/second. tenant_id leads every index. Shard across eight primaries. One tenant holds 22% of all rows and by itself exceeds a single shard's write capacity. Design the routing, the split of that tenant, and the online move of a tenant between shards with writes continuing. State what breaks for queries that are tenant-scoped today, and exactly what a write must do when it arrives at the old shard after the cutover.

Approach

  1. Route on a unit smaller than a tenant from the start. Make the routing key (tenant_id, bucket) with a fixed bucket count - 64 over eight shards - and keep a directory mapping each (tenant_id, bucket) to a shard, carrying a version and cached in every service. An ordinary tenant has all 64 buckets pointing at one shard and behaves exactly as it does today; only the hot tenant has its buckets spread. Hashing tenant_id alone spreads tenants evenly, gives you no way to move one, and has no answer at all for a tenant larger than a node. The bucket count is the part you cannot change later without rehashing rows, so pick it well above the shard count and rebalance by moving buckets, not by re-bucketing.
  2. For the tenant that exceeds one node, its buckets must land on different shards - that is the whole point of bucketing it, and buckets confined to its own shard would rename the rows while leaving every write on the node whose ceiling it already exceeds. Size it from measured numbers rather than from its row share: 22% of rows says nothing about write rate. The current primary tops out near 1.2k writes/second on this hardware and workload, so a tenant peaking at W writes/second needs its buckets spread over at least ceil(W / headroom-per-shard) shards, where the divisor is the share of each shard's ceiling you are willing to give it while that shard still serves other tenants - not the full 1.2k. Size on its peak, not its mean.
  3. Fix the co-location invariant at the right grain. What must commit in one transaction is a resource, its resource_revision row and its outbox_event row, so the bucket is a property of the resource: derive it once at creation and stamp it into resource_id, and every later revision and event routes with its parent for free. Per-tenant co-location was never the requirement, and mistaking it for one is what makes a tenant look unsplittable. What genuinely breaks is an invariant spanning two resources of one tenant - a per-tenant counter, uniqueness across its resources - which now needs either a home-shard table or two-phase commit, and 2PC at this write rate is not a serious option.
  4. Keep the idempotency constraint arbitrating, because it is now enforced per shard. PRIMARY KEY (tenant_id, idempotency_key) only continues to reject a retry if the same key always lands on the same shard, so derive the create-path bucket from hash(tenant_id, idempotency_key) and mint the new resource_id inside that bucket, which also puts the key row and the resource it guards in one transaction. A bucket chosen from anything that differs between a request and its retry - a timestamp, the worker id, a client-supplied resource id - splits one key across two shards, both inserts succeed, and the write endpoint's retry safety is silently gone.

Follow-up

  • The fence lasts 90 seconds instead of 4 because the final delta keeps growing. What is happening, and what do you do while the tenant is fenced?
  • Two tenants must merge into one account. What does that cost under this scheme, and which step is not reversible?

One log partition stops advancing while the others drain

Easy · poison message · head-of-line blocking · consumer lag

Search results for a subset of tenants are hours stale; the rest are current. The projection consumer reports lag of zero on 15 of 16 partitions and 400,000 on one. Its error rate is flat and its CPU is idle. outbox_event has no pending rows older than a second, so the relay has published everything it holds. Identify the mechanism, give the ordered checks, and state what you do in the first ten minutes versus what you change permanently.

Approach

  1. Read the lag distribution first. A slow consumer lags everywhere; zero on fifteen partitions and 400,000 on one is not throughput. Idle CPU on the stuck partition means the consumer is not advancing its offset at all, which points at one message it cannot get past rather than at a rate problem.
  2. Exonerate the producer before touching the consumer. No pending outbox rows older than a second means the relay published, so the event exists in the log. This separates never sent from sent and never applied, which are different code paths and usually different owners.
  3. Read the message at the stuck offset and the handler's log lines for its event_id. A flat error rate with no progress has two explanations and you must distinguish them: the handler is throwing and the retry loop is swallowing it, or the handler is blocking on something and never returning. Idle CPU with no error lines favours the second.
  4. Mitigate before diagnosing further. Move the offending event to a dead-letter store and commit the offset past it. Adding consumers does nothing here, because a partition is consumed by exactly one member of the group, and the blast radius is every aggregate hashed to that partition, not only the aggregate that produced the bad event.

Follow-up

  • The dead-lettered event carried aggregate_version 7 and the projection had applied 6. What must the replay do differently if 8 and 9 landed in the meantime?
  • How do you show staleness to the user while the partition is behind, given the API already returns the projection's watermark?

Suggested practice checklist

Built from the topics and questions Impetus candidates report; no round sequence has been reported.

Day 1 — Establish the Impetus format

  • No round sequence has been reported, so ask your recruiter for the sequence, the duration of each stage and whether you will write code.

Deliverable: A written reply from your recruiter confirming the format.

Day 2 — Work Data Structures & Algorithms (DSA)

  • Spend the session on Data Structures & Algorithms (DSA), which Impetus candidates report being tested on.
  • Write one worked example in Data Structures & Algorithms (DSA) and time yourself on it.

Deliverable: One timed worked example in Data Structures & Algorithms (DSA).

Day 3 — Work Database Management Systems (DBMS)

  • Spend the session on Database Management Systems (DBMS), which Impetus candidates report being tested on.
  • Write one worked example in Database Management Systems (DBMS) and time yourself on it.

Deliverable: One timed worked example in Database Management Systems (DBMS).

Day 4 — Work Structured Query Language (SQL)

  • Spend the session on Structured Query Language (SQL), which Impetus candidates report being tested on.
  • Write one worked example in Structured Query Language (SQL) and time yourself on it.

Deliverable: One timed worked example in Structured Query Language (SQL).

Day 5 — Answer out loud: Core Computer Science Fundamentals

  • Answer aloud, timed: Explain the difference between process and thread in an Operating System.
  • Answer aloud, timed: How do you handle deadlocks in a multi-threaded application?

Deliverable: Spoken answers to 2 reported Core Computer Science Fundamentals question(s), under time.

Day 6 — Answer out loud: Data Structures and Algorithms

  • Answer aloud, timed: Given an array, how would you find the subarray with the largest sum?
  • Answer aloud, timed: How do you implement a queue using two stacks?

Deliverable: Spoken answers to 2 reported Data Structures and Algorithms question(s), under time.

Day 7 — Dry run for Impetus

  • Run one full mock under time, then write down the two questions you most want to ask your interviewers.

Deliverable: A completed timed mock and two questions to ask.

Behavioural preparation

Behavioural rounds judge the decision you made and what it cost.

How do you handle deadlocks in a multi-threaded application?

Medium · Core Computer Science Fundamentals

Approach

  1. Pick a story where you made the decision, not one where you watched it.
  2. State the situation in two sentences and spend the rest on the reasoning.
  3. Give the blast radius: what could have broken, and what you measured.
  4. Name the disagreement and how you resolved it with evidence.

Follow-up

  • What would you do differently if you ran that again?
  • How did you know your change caused the improvement?

Estimate work you have never done and defend the range

Hard · estimation · backfills · expand-contract

You are asked to estimate a change you have never attempted: add a column to a 100-million-row table, populate it, move reads across, and drop the old shape. Give a range with the assumptions that generate it, including batch size, the signal your backfill throttles on, and wall-clock hours, and name the three unknowns that would move the number most. Then describe a real estimate you gave under comparable ignorance: how you expressed its uncertainty, what you committed to, and how wrong you turned out to be.

Approach

  1. Decompose into independently deployable steps before estimating anything: add the column nullable, write both shapes, backfill in batches, verify, move reads, stop writing the old shape, drop it. That is four deploys spread over days, and the calendar estimate is dominated by them rather than by the loop's runtime.
  2. Do the arithmetic aloud for the part that has arithmetic in it: batch size times number of batches times per-batch duration, at a write rate the primary can absorb alongside roughly 1.2k writes per second of production traffic. The loop is throttled by replication lag and lock waits, not by how fast it can issue statements.
  3. Price the schema step by its lock rather than its statement duration. In PostgreSQL an ALTER TABLE taking ACCESS EXCLUSIVE waits for every open transaction on that table while later queries queue behind it, so a millisecond change issued during a thirty-second analytics query stalls that table for thirty seconds. Adding a nullable column with a non-volatile default avoids a rewrite from version 11; a new index wants CREATE INDEX CONCURRENTLY, which cannot run inside a transaction block and leaves an invalid index behind if it fails.
  4. Express the answer as a range whose endpoints each trace to a stated assumption, then name the cheapest experiment that collapses it, which is almost always running one real batch against the real table and multiplying.

Follow-up

  • How do you verify the backfill genuinely finished, given rows written by production traffic while it ran?
  • Where does the backfill resume from after a worker is killed mid-batch, and what makes that resume point trustworthy?

Unblock an engineer without taking the keyboard

Easy · mentoring · leases · at-least-once

A teammate has spent two days on a job handler that occasionally writes duplicate rows. They are certain the queue is delivering twice by mistake. You suspect a lease expiring under a slow handler, so the job is running concurrently with itself. Describe how you have unblocked someone in this position: what you asked before offering a hypothesis, what you showed them rather than told them, and what you left them owning. Then say what you would do if their theory turned out to be the right one.

Approach

  1. Ask before diagnosing, and ask for things answerable from data they already have: the attempt count on the job rows that produced duplicates, the handler's observed duration against its lease expiry, and whether the duplicate rows share a natural key that a unique constraint could have caught.
  2. Teach the shape rather than the answer. A lease cannot distinguish a dead worker from a slow one, so a handler that outruns its lease is running twice by design, and deploys deliver the other half by killing handlers mid-run on every rollout. Both of their candidate theories produce identical duplicate rows, which is why the evidence has to come from timings rather than from argument.
  3. Hand over a checklist they execute: a natural key on every write the handler performs so the second copy collides rather than appends, the record of intent written before any external effect, a lease heartbeat while running, and the metric that shows it working.
  4. Keep ownership with them deliberately. Pair on the first write, then step back; if you finish it yourself you have closed one ticket and left the same person stuck on the next redelivery.

Follow-up

  • How would you distinguish a genuine double-delivery from a lease expiry using only the data already stored?
  • Their handler calls an external endpoint before recording that it did. What do you tell them to change first?