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Avnet Software Engineer Interview Questions & Guide 2026

Software engineer interview prep for Avnet: original coding, system design and debugging practice, each with a worked solution.

The 60-second brief

As a Software Engineer at Avnet, you play a vital role in building and maintaining the technological ecosystem that powers global electronic components distribution, supply chain solutions, and embedded systems engineering. Your work directly impacts how internal operations run, how client-facing applications perform, and how hardware architectures integrate with software layers. Whether you are developing robust backend services, designing middleware solutions, or working close to the hardware with embedded devices, your contributions directly support a Fortune 500 enterprise with massive operational reach.

Treat capacity estimation as a conversion skill rather than a table to memorise: turn a user count and an action rate into requests per second and bytes per day, then name the component that number breaks first. The figure only matters if it changes the design.

Focus areas

  • Build at-least-once pipelines with explicit deduplication horizons
  • Keep money in integer minor units
  • Make every write idempotent under client retries

Overview

This role requires a balance of core software engineering rigor and domain adaptability. You might find yourself collaborating with hardware teams on FPGA communication, optimizing database queries for high-volume logistics, or deploying cloud-based solutions that streamline enterprise workflows. Because Avnet bridges the gap between semiconductor manufacturers and end-user design engineers, your technical solutions must be scalable, reliable, and capable of handling complex, data-intensive environments.

Expect a collaborative environment where cross-functional alignment is just as important as writing clean code. You will regularly interface with product managers, system managers, and infrastructure teams to deliver solutions that meet strict business timelines. Success in this role requires intellectual curiosity, a solid grasp of fundamental computer science principles, and a willingness to understand the unique hardware-software integration challenges inherent in the electronics distribution industry.

The Avnet interview process

Avnet candidates report 4 rounds · ≈ 3-5 weeks. The stages below are what candidates describe, not a published process.

Screening Call

The person on this call usually cannot evaluate your code and does not need to. They write a short paragraph, and that paragraph is what a hiring manager skims when deciding who to put on your loop. So the test is not whether your work was hard, it is whether a non-engineer can repeat it correctly. Name systems by what they did rather than by their internal codename, give each project a shape (what was breaking, what you changed, what happened after), and keep the whole walkthrough near ninety seconds. Depth that cannot survive a paraphrase reads as vagueness.

What to demonstrate

  • Whether a non-engineer can restate your projects without distorting them, since their paraphrase is what travels to the hiring manager, not your sentences
  • Whether each project has a shape rather than a stack list: the failure or constraint, the change you made, the result and how it was measured
  • Whether you can say what was yours inside a team project without either inflating it or disappearing into the plural

How to prepare

  • Rewrite each headline project as two sentences with no internal system names and no acronyms outside your company, then say them to someone outside engineering and have them repeat them back. Fix whatever came back wrong
  • Attach one measured number to each project: the baseline, the change, and the window it was measured over. Where nothing was ever measured, say that plainly rather than reaching for a plausible percentage
  • Time the background walkthrough against a clock. If it runs past two minutes, compress the earliest role to a single clause and spend the recovered time on the most recent one

Technical Assessment

Most of the time lost in this format is not lost to thinking. It goes to a standard-library call you half-remember, an off-by-one in a loop bound, and a debugging loop that mutates code at random until something passes. When output is wrong, stop re-reading the whole function: take the smallest input that reproduces it and walk the state through by hand, printing intermediates if the environment allows. Guessing at a fix without a failing case you understand is how a five-minute bug becomes twenty, and the clock does not pause while you do it.

What to demonstrate

  • Whether you reach the right structure without a detour, and can write it from memory rather than only recall that one exists
  • Whether overflow is considered where the language has fixed-width integers, since a signed 32-bit value stops at 2,147,483,647 and then wraps in Java, is undefined behaviour in C++, and does not arise in Python, whose integers grow instead
  • Whether recursion depth is treated as a constraint on large inputs, given that CPython's default limit is 1000 frames and a deep recursion can exhaust the stack in any language where an iterative version would not
  • Whether a failing case is isolated and explained before any edit is made to the code

How to prepare

  • From an empty file and with no references open, implement the pieces you lean on most: a heap push and pop, an iterative DFS with an explicit stack, and a binary search whose midpoint is written lo + (hi - lo) / 2, which avoids the overflow that (lo + hi) / 2 can hit in a fixed-width integer type
  • Time yourself on the ten library calls you look up most, such as sorting with a custom comparator, splitting and joining strings, and finding the next key at or above a value in an ordered map, until the lookup is gone
  • Take a solution you know is broken and, before touching it, write one sentence naming the input, the expected value and the actual value. Repeat until you do it without deciding to.

Team Discussions

When a round has no standard shape, it is often there because something is still open: an area no earlier conversation reached, a round where the signal came out mixed, or a decision someone is not ready to make alone. Work out which by going back over what each earlier round actually covered rather than how it felt, and arrive able to give evidence on that point without being asked twice. Weak answers replay the loop's earlier material at the same depth. Strong ones go a level deeper and stay consistent with what you already said.

What to demonstrate

  • Whether your account of a project matches the one you gave earlier in the loop, since what you said before may be available to whoever runs this round
  • Whether you can go a level deeper on something already covered, reaching the decision and its alternatives rather than repeating the summary
  • Whether you state your own uncertainty accurately, including parts of a system you did not build and decisions you inherited, instead of claiming even ownership across all of it
  • Whether you can answer a question you handled poorly earlier by naming what you missed, rather than delivering a polished second version as if the first had not happened

How to prepare

  • Reconstruct the loop on one page: for each round, the questions you were asked and the answer you actually gave, not the better one you thought of afterwards. The gaps on that page are your best available guess at why this round exists.
  • Take the two claims you made earlier that carry the most weight and assemble the backing for each: the measurement, the date, what broke, the decision you would make differently now.
  • Write down the three facts about your work that must not drift between tellings, such as team size, timeline and your own role, and check your stories against that list rather than trusting recall under pressure

Behavioral Interview

This round is deciding whether a change you make without supervision can be allowed to reach production. It is scored on what you knew at the moment you decided, not on how it turned out, so a story that opens with the result and works backwards reads as luck retold as judgement. Say what the options were, what you did not know, what you did to shrink the unknown before committing, and what you accepted as the worst plausible case. The detail that separates answers is a bound: how many users, how much data, and for how long, if you had been wrong.

What to demonstrate

  • Whether the reasoning you give was available at the time you decided rather than after the result came in, since a story whose deciding evidence arrived later describes an outcome and not a judgement
  • Whether you can put units on the exposure (users, rows, minutes of degraded service) and whether the containment you chose actually bounded it: a canary bounds the request path it fronts, while a background job writing to a shared table reaches every user regardless of which version served their requests
  • Whether the reversal path existed before you shipped or was improvised during the incident, and whether it restores state or only stops further damage

How to prepare

  • For your three largest changes, write down the one thing you would have had to be wrong about for it to fail, and what your best estimate of it was on the day you shipped. If you never held an estimate, that is the gap the follow-up questions will find
  • Write the undo procedure for one of those changes as it existed at the time, then mark which steps restore data and which only stop new damage. Turning a flag off or reverting a deploy ends the new writes; rows already written come back only from a copy you kept, and a dropped column comes back empty unless something outside the schema holds the values
  • Rehearse one story from the decision point forward and stop before the outcome, then have someone ask what you would do next. If the story only works with the ending attached, it is an anecdote rather than a decision you can defend

Where candidates lose points

Serialising a tenant's writes through select ... for update on a single counter row

It is the first change that makes a counter correct, and it caps that tenant's write throughput at roughly one divided by the lock hold time. A transaction that takes the lock, makes a network call and then commits holds it for the entire round trip: at 2 ms that is about 500 writes per second for the whole tenant, and the largest tenants are exactly the ones that exceed it. The damage then spreads, because every waiter holds a database connection while it queues, so one hot tenant drains the shared pool and the symptom presents as a site-wide latency incident rather than as a lock problem. The repairs are to shrink the critical section to a single statement, to shard the counter into per-(tenant, hour) or per-(tenant, bucket) rows and sum on read, or to batch in memory and flush periodically while accepting the bounded loss that batching implies.

Paginating a growing table with limit and offset

Two unrelated defects share the idiom. Correctness: rows inserted or deleted between page requests shift the window, so a consumer walking an export skips rows and sees others twice, which for a customer-facing sync is silent data loss rather than an error anyone notices. Cost: the database still produces and discards the skipped rows, so page N costs time proportional to N times the page size and a deep page on a large table degrades from milliseconds to seconds. Keyset pagination over a stable, unique, indexed ordering -- where (created_at, id) < ($1, $2) order by created_at desc, id desc limit $3 -- is constant-cost per page and immune to shifting, on the precondition that the cursor columns never change value for a row, which disqualifies updated_at as a cursor.

Reading the constraints as preamble rather than as part of the problem

The bounds are usually there to eliminate the obvious approach: n up to 10^5 makes an O(n^2) scan roughly 10^10 operations, far outside any per-test time budget, and an input larger than memory rules out loading it at all. When a bound is not given, ask for it, then say out loud which approach it kills.

A queue or buffer with no bound

Every producer-consumer boundary needs a capacity and a policy for reaching it: block the producer, shed load, or drop the oldest entry. Unbounded buffering converts a temporary slowdown into memory exhaustion and hides the backpressure signal that would have revealed the consumer was falling behind.

Questions & practice

What is the purpose of a try-catch statement?

Medium · languages, concurrency and fundamentals

Approach

  1. Identify the window where an invariant is briefly untrue.
  2. Reach for the cheapest primitive that closes the race, not the broadest lock.
  3. Say what the runtime actually does before reasoning about the code.

Follow-up

  • How would you prove the race exists rather than suspect it?
  • Where could this allocate more than you expect?

What do you like about Linux, and how do you use it in your workflows?

Medium · languages, concurrency and fundamentals

Approach

  1. Say what the runtime actually does before reasoning about the code.
  2. Identify the window where an invariant is briefly untrue.
  3. Distinguish a value from a reference to it, and say which one you handed out.

Follow-up

  • What happens if two callers reach this at the same time?
  • How would you prove the race exists rather than suspect it?

Fold a deduplicated usage stream into hourly rollups

Easy · aggregation · deduplication · watermarks · exact-arithmetic

You are given one day of usage_event rows, up to 250 million, each carrying event_id, tenant_id, workspace_id, environment, sku, quantity numeric(20,6), idempotency_key, occurred_at and ingested_at. Produce usage_rollup_hourly cells keyed (tenant_id, workspace_id, sku, hour_start) with quantity_sum, event_count and source_max_ingested_at. An event counts once per (tenant_id, idempotency_key). The rollup grain has no environment column, so state your filter. One pass. Give your time and space bounds, and say what the deduplication actually costs in memory.

Approach

  1. Bucket on occurred_at, never ingested_at: hour_start = date_trunc('hour', occurred_at at time zone 'UTC'). The two columns answer different questions. occurred_at says which hour the customer is billed for; ingested_at says how current the fold is. Using the second for the first makes late data invisible instead of correctable.
  2. The fold is trivial and the deduplication is the entire cost, so price it before designing anything clever. An exact set over (tenant_id, idempotency_key) at 250M entries, stored as a 16-byte 128-bit hash in an open-addressed table at 0.7 load factor, needs about 357M slots at 16 bytes each, roughly 5.7 GB. The fix is partitioning by hash(tenant_id) % P so each shard holds 1/P of the set and no tenant's keys straddle shards.
  3. Rule out a Bloom filter as a replacement, in the right direction: a false positive reports 'already seen' for an event never seen, so you drop a real event and lose revenue with no error raised. It is usable only as a negative pre-filter in front of the exact set, where a miss is conclusive and a hit must fall through to the real lookup.
  4. Accumulate in scaled integers, not binary floating point. numeric(20,6) admits values below 10^14, so one event scaled to micro-units can reach 10^20, past int64's 9.22 x 10^18; use a 128-bit or arbitrary-precision accumulator unless you first bound the per-event maximum. binary64 represents integers exactly only to 2^53, about 9.01 x 10^15, and cannot represent 0.1 at all, so two runs that sum in different orders disagree.
  5. Carry source_max_ingested_at = max(ingested_at) over the events folded into each cell, and count event_count over accepted, post-dedup events. Without that watermark there is no way to prove later what a number did and did not include, which is the first question any reconciliation asks.
  6. State the environment filter explicitly, because the rollup grain cannot record it. A fold that quietly includes staging bills non-production traffic; one that quietly excludes it loses a cost signal. Production-only is the billing answer, and either way it belongs in the job name and the output metadata. Complexity: O(n) time, O(distinct dedup keys) space, dominated by the dedup set rather than by the cells.

Worked solution (25 min)

  1. Write both key tuples down before any code: dedup key (tenant_id, idempotency_key), cell key (tenant_id, workspace_id, sku, hour_start), with hour_start derived from occurred_at in UTC.
  2. Build a 10,000-row fixture containing one event duplicated three times under the same idempotency_key, two events sharing an idempotency_key across different tenant_id values, one event whose occurred_at is two hours before its ingested_at, and one staging event inside an otherwise production cell.
  3. Fold it and assert each of those four expectations separately rather than eyeballing a grand total.
  4. Re-run with the input shuffled and diff the output files.
  5. Size the dedup set for 250M keys using the load-factor arithmetic and write the number down next to the fixture.

Expected result: The triplicate contributes one event and its quantity once. The two same-key, different-tenant events both count, because the dedup key is the pair. The late event lands in the hour of its occurred_at while that cell's source_max_ingested_at advances to the later timestamp. The staging event is included or excluded per the stated filter and never silently.

Verify it yourself

  • Shuffled input produces byte-identical cells, including event_count and source_max_ingested_at.
  • The sum of quantity_sum across all cells equals the sum of quantity over the distinct dedup keys, computed independently.
  • Swapping the accumulator to binary64 makes a fixture of 0.1-valued quantities disagree with the exact sum. That is a failing test, not a rounding note.

Follow-up

  • A producer retries at 23:59:59 and the retry lands at 00:00:01. The unique index on the daily-partitioned table must include the partition key. What gets double-counted, and what is the smallest change that fixes it?
  • The consumer acknowledges its batch before committing the fold. Which failure loses revenue now, and which arrangement duplicates instead?
  • What makes a re-run over the same day produce byte-identical rollups?

Decide which facts an invoice line copies instead of joining

Medium · denormalisation · immutable records · foreign keys · rounding

invoice_line_item already denormalises tenant_id, which is reachable through invoice_id, and stores amount_minor even though quantity times unit_price_micros would recompute it. A reviewer asks you to normalise both away, and separately asks whether the tenant's legal name and billing address should be copied onto the invoice header. Decide each case. For every field you keep denormalised, name the read pattern or the invariant that justifies it, the anomaly the copy can develop, and the mechanism that prevents that anomaly here.

Approach

  1. Split the question into two kinds of copy, because they fail differently. A copy of a currently mutable fact is a cache: it drifts and needs invalidation. A copy of a fact frozen at write time is not a cache at all, it is the record of what happened, and normalising it away destroys information the source no longer holds.
  2. Keep tenant_id on the line. It costs 8 bytes, it leads every index on the table so no read is ever accidentally cross-tenant, and it turns a wrong join into an empty result rather than another tenant's money. Prevent the drift structurally: a unique constraint on invoice (invoice_id, tenant_id) plus a composite foreign key from the line on (invoice_id, tenant_id) makes a mismatched pair impossible, so the database enforces agreement instead of a code review.
  3. Keep amount_minor. Rounding must happen exactly once, at a named site, with a stated mode (half-even here). If readers recompute from quantity and unit_price_micros, every reader owns a rounding decision, and half-up and half-even diverge systematically across thousands of lines rather than cancelling out. A check constraint can bound the stored value but deliberately cannot re-derive it.
  4. Copy the legal name and billing address onto the invoice header, written once and never updated. The statement must show what was true when it was sealed, and the tenant record will change afterwards. This is a snapshot for the same reason source_rollup_watermark is stored per line: without it, nobody can reconstruct what the customer was told.
  5. Name the read pattern that pays for all of it. Rendering, dispute response and export are per-tenant, per-period reads over thousands of lines that would otherwise join back to slowly changing dimensions that no longer hold the historical value. The write side is a once-per-period batch, so the extra columns cost nothing that matters.
  6. Concede the case where the reviewer is right: a mutable operational attribute such as the tenant's current plan name has no business on a line. If a report wants it, join. If a statement needs the plan as of the period, that is another snapshot and it belongs on the header with the rest.

Follow-up

  • Write the composite foreign key and the unique constraint it requires on the parent. What does it cost on every line insert, and what does it do to a bulk load?
  • A tenant is renamed after being invoiced. Which rows change, and what does the customer see on last quarter's PDF?
  • Where does currency live, and what breaks if a tenant's billing currency changes between two periods?

Migrate a live partitioned event table without blocking ingest

Hard · online migration · ddl locks · expand and contract · partitioning

usage_event is range-partitioned daily on ingested_at, holds roughly 250M rows per day across 400 live partitions, and is written at 10-40k rows/second. Two changes are required: quantity must move from double precision to numeric(20,6), and a new environment column must become NOT NULL with a default of 'production'. Ingest cannot stop. Give the ordered plan, naming for each step the lock it takes, what that lock blocks, and roughly how long it is held. Identify the one step that cannot be rolled back cleanly once traffic depends on it.

Approach

  1. Classify the two changes before planning anything. Adding a column with a non-volatile default has been metadata-only since PostgreSQL 11, so it is cheap. Changing double precision to numeric is not binary-coercible, so alter column ... type rewrites every partition under ACCESS EXCLUSIVE and rebuilds its indexes; on this volume that is hours of blocked ingest and is simply not an option, which is why the plan is expand-and-contract rather than one statement.
  2. Expand: add quantity_numeric numeric(20,6) and environment with its default on the parent. Both are catalogue-only but both take a brief ACCESS EXCLUSIVE that cascades to partitions, so run each with lock_timeout set to a second or two and retry on failure. A queued ACCESS EXCLUSIVE request blocks every reader behind it, which is how a metadata-only change turns into an outage.
  3. Dual-write: deploy producer code that populates both columns on every insert, and leave it running before anything reads the new column. This is the step that cannot be reverted cleanly. Once readers depend on quantity_numeric, reverting the writer leaves rows with a null there, and the gap is only discoverable by re-reading the old column, which the readers have stopped doing.
  4. Backfill older partitions in batches keyed on the primary key, oldest first, committing every few thousand rows with a pause between batches, and skipping the partition still receiving writes until it rotates. Each batch is an ordinary UPDATE taking row locks only. The cost is bloat and WAL rather than blocking, so watch dead tuples and let autovacuum keep pace instead of wrapping 400 partitions in one transaction.
  5. Make NOT NULL cheap with the three-step form: add constraint ... check (environment is not null) not valid (brief ACCESS EXCLUSIVE, no scan), then validate constraint (SHARE UPDATE EXCLUSIVE, scans while reads and writes continue), then set not null, which from PostgreSQL 12 uses the validated check and skips its own full scan. Do this per partition, then on the parent.
  6. Switch and contract: move reads to the new column behind a flag, verify over a full period that both columns agree on freshly written rows, drop the old column (metadata-only), and only then remove the dual-write. Any index on the new column goes on with CREATE INDEX CONCURRENTLY per partition, since CIC is not supported on a partitioned parent: create the parent index with ONLY, build each child concurrently, then ALTER INDEX ... ATTACH PARTITION until the parent index becomes valid.

Worked solution (45 min)

  1. On a scratch cluster, build 10 partitions of 2M rows each and run a writer at a few thousand inserts/second.
  2. Run the naive type change and measure how long writes stall and how far ingest lag grows before killing it.
  3. Run the expand step with lock_timeout = '2s' while the writer runs, and observe a clean lock timeout and retry instead of a pile-up of blocked readers.
  4. Backfill in 5k-row batches and chart dead tuples and WAL generated per batch.
  5. Run the not-valid, validate, set-not-null sequence and confirm from pg_stat_activity and timings that nothing held an exclusive lock through a full scan.
  6. Add an index with CIC per partition plus ATTACH PARTITION and confirm the parent index reports valid only after the last attach.

Expected result: An ordered expand, dual-write, backfill, switch, contract plan with the lock named per step: metadata-only ADD COLUMN under a brief ACCESS EXCLUSIVE taken with lock_timeout; batched UPDATE backfill under row locks; CHECK NOT VALID, then VALIDATE under SHARE UPDATE EXCLUSIVE, then SET NOT NULL; CREATE INDEX CONCURRENTLY per partition with ATTACH PARTITION; and the dual-write-to-read switch identified as the step that cannot be reverted cleanly.

Verify it yourself

  • No step in the plan holds ACCESS EXCLUSIVE for longer than the configured lock_timeout.
  • The writer's error rate stays at zero through the rehearsal apart from the deliberate lock timeout.
  • After VALIDATE, SET NOT NULL completes in milliseconds on a table where the naive form scanned every row.
  • Freshly written rows agree on both columns for a full verification period before the old column is dropped.

Follow-up

  • A CREATE INDEX CONCURRENTLY fails halfway through the partition list. What state is the table in, how do you detect it, and what do you run?
  • The producer computes quantity itself. What happens to a request already in flight when the dual-write deploy lands, and does it matter?
  • Give two queries that prove the backfill is complete: one cheap enough to run every minute, one authoritative.

Can you solve coding problems involving strings and graph data structures?

Medium · system design and architecture

Approach

  1. State the consistency you need, and where you are willing to be stale.
  2. Choose a partition key and say what query it makes expensive.
  3. Fix the scope first: who calls this, how often, and what they do when it fails.

Follow-up

  • What breaks first when traffic grows ten times?
  • How does this behave when that dependency is down for an hour?

Can you explain basic concepts of cloud architecture and deployment?

Medium · system design and architecture

Approach

  1. State the consistency you need, and where you are willing to be stale.
  2. Choose a partition key and say what query it makes expensive.
  3. Name the failure you are designing for, then the recovery path.

Follow-up

  • How does this behave when that dependency is down for an hour?
  • What would you drop to keep the system up under load?

How do you approach designing a scalable backend service?

Medium · system design and architecture

Approach

  1. Name the failure you are designing for, then the recovery path.
  2. Fix the scope first: who calls this, how often, and what they do when it fails.
  3. Choose a partition key and say what query it makes expensive.

Follow-up

  • What breaks first when traffic grows ten times?
  • What would you drop to keep the system up under load?

Why should we choose a computer science graduate over an electronics and communication engineering graduate for this role?

Medium · api and integration design

Approach

  1. State how the contract changes without breaking existing clients.
  2. Say who the caller is and what they do when the call fails halfway.
  3. Separate accepted, pending, failed and confirmed; they are different facts.

Follow-up

  • What happens if the caller retries after a timeout?
  • How does a client discover it is on an old version of this contract?

Have you worked with embedded devices such as Linux u-boot, kernel, Zephyr, camera sensors, or audio devices?

Medium · api and integration design

Approach

  1. Separate accepted, pending, failed and confirmed; they are different facts.
  2. Say who the caller is and what they do when the call fails halfway.
  3. Define the identity of a request so a retry cannot double-apply it.

Follow-up

  • What happens if the caller retries after a timeout?
  • What does a partial failure look like to the caller?

Which families of Xilinx FPGA do you know of?

Medium · api and integration design

Approach

  1. Design the error taxonomy before the success shape; callers branch on it.
  2. Separate accepted, pending, failed and confirmed; they are different facts.
  3. State how the contract changes without breaking existing clients.

Follow-up

  • What happens if the caller retries after a timeout?
  • What does a partial failure look like to the caller?

Build a resumable usage export the customer can reconcile against

Medium · pagination · cursors · late data

Customers reconcile invoices against usage_event (event_id uuid, tenant_id, workspace_id, environment, sku, quantity numeric(20,6), idempotency_key, occurred_at, ingested_at, source_service, request_id), partitioned daily on ingested_at. The current export is ?page=N&per_page=1000 ordered by occurred_at, and a customer syncing hourly reports rows that never appear in their export but do appear on their invoice. Design the replacement: the ordering, the cursor's contents, the index it requires, and the rule deciding where a page stops. State what the client does on a timeout and on a cursor older than retention.

Approach

  1. Separate the two defects in the current shape. Offset makes the database produce and discard N * per_page rows, so page cost grows linearly and a deep page degrades from milliseconds to seconds. Concurrent inserts also shift the window between requests, so a walker skips rows with no error raised anywhere, which for a customer sync is silent data loss.
  2. Order by ingestion, not by occurrence. During a replay events arrive hours out of occurred_at order, so a consumer holding an occurred_at high-water mark can never see a late event that falls below it; (ingested_at, event_id) is the only ordering under which 'everything after my cursor' is a complete statement.
  3. Page with a row comparison: where tenant_id = $1 and (ingested_at, event_id) > ($2, $3) order by ingested_at, event_id limit $4, backed by an index on (tenant_id, ingested_at, event_id). That seeks directly to the resume point, so every page costs the same regardless of depth.
  4. Trail the head of the table. With ingested_at defaulting to now(), which is transaction start time, a long insert transaction receives an earlier timestamp and becomes visible after a reader has already passed it. Cap each page at ingested_at <= now() - delta, with delta larger than the longest write transaction as bounded by statement_timeout and idle_in_transaction_session_timeout, or the export skips exactly the rows written under load.
  5. Make the cursor opaque and self-describing: base64 of the timestamp, the event id and a fingerprint of the filters, rejected when the filters differ from the current request. Return 410 with a cursor_expired code once the cursor's partition has been dropped, so the client restarts from a known time instead of resuming into a hole.
  6. Keep a page a pure GET with no server-side consumption, so a timeout is resolved by retrying the identical cursor.

Worked solution (30 min)

  1. Construct the failing case on paper: an event with occurred_at at 09:00 ingested at 14:00, and a consumer that read up to 10:00 at 11:00.
  2. Write the keyset query with the row comparison and the exact index it needs, then say which column of the index each predicate uses.
  3. Add the trailing-head predicate and pick delta from a named timeout setting rather than a round number.
  4. Define the cursor's encoded contents and the two error cases: filter mismatch and expired partition, with their status codes.
  5. Write the client's algorithm in four lines: request, persist cursor after processing the page, retry the same cursor on timeout, restart from a time on 410.

Expected result: Keyset pagination over (ingested_at, event_id) with an index on (tenant_id, ingested_at, event_id), a trailing head predicate sized above the longest write transaction, an opaque filter-bound cursor, and 410 for a cursor past retention.

Verify it yourself

  • A late event with an old occurred_at is still delivered by the export.
  • Page cost is independent of how many pages have already been read.
  • The cursor persists across a client restart and survives retrying the same page.
  • The tie-break column is unique, so no row can be skipped or repeated at a page boundary.

Follow-up

  • The customer asks for a total count alongside the first page. What do you offer instead, and why is an exact count both expensive here and wrong by the time it is read?
  • How would you let a customer re-read a window they have already consumed without giving up the forward-only cursor?

Invoice detail latency triples after an ORM relationship refactor

Easy · n+1 query · orm · latency regression

An invoice detail endpoint returned in 40 ms at p99 last week. After a refactor replaced a hand-written join with ORM relationship access it returns in 1.4 s, and the regression grows with the number of invoice_line_item rows on the invoice. Database CPU rose, but no statement in the slow-query log exceeds 3 ms. You have request traces with per-span SQL, the ORM statement log, and a staging copy of the data. Produce an ordered diagnostic checklist, the measurement that confirms the cause before any code change, and the fix.

Approach

  1. Count statements per request before reading any statement duration. A slow-query log hides this class by construction, because every individual query is fast and only their number is wrong; take one trace and count SQL spans.
  2. Establish proportionality rather than asserting it: sample invoices with 5, 20, 60 and 200 line items and plot statements per request against line count. A straight line of slope 1 through an intercept of one or two identifies a lazy relationship load, and no index or cache would move that line.
  3. Locate the emitting attribute access in the refactored code and check whether the same shape repeats one level deeper, for instance a tax or adjustment collection hanging off each line, which turns the cost quadratic.
  4. Fix with a bounded statement count: either one join that fetches invoice and lines together, or two statements where the second is WHERE invoice_id = $1 AND tenant_id = $2. Keep tenant_id in the predicate so the read stays tenant-scoped even though invoice_id already implies it.
  5. Choose between the two deliberately: the join duplicates the wide parent row across N children on the wire, the two-statement form avoids that for one extra round trip. Prefer the join for narrow parents and the split for wide ones.
  6. Pin it with a per-request statement-count assertion in a test that varies line count, because a latency assertion passes on a small fixture and would not have caught this.

Follow-up

  • The endpoint now also needs per-line tax rows. Show the shape that keeps statement count constant instead of reintroducing the same defect one level down.
  • How does this change if a transaction-pooling proxy sits between the service and the database, so each statement may land on a different backend session?
  • The same page paginates invoices with LIMIT and OFFSET. Why is that a second, independent defect, and what replaces it?

Suggested practice checklist

Day one measures instead of guessing, under a fixed rubric, and the remaining hours are allocated in proportion to the gaps before any studying begins. The allocation is deliberately not renegotiated midweek, because the area that feels worst on day three is usually the one that is moving.

Day 1 — Diagnostic, scored before you study anything

  • Sit a 110-minute diagnostic in four blocks: forty-five minutes on two coding problems, twenty-five on one design prompt taken to interface and data model, twenty of short-answer fundamentals, and twenty delivering two behavioural answers aloud.
  • Score each block from 0 to 3 on a fixed rubric where 3 is correct and fluent, 2 is correct but slow or prompted, 1 is partially correct and 0 is stuck, grading the artifact rather than how the attempt felt.
  • Allocate days two to five in proportion to 3 minus each block's score, write the allocation down, and commit to leaving it alone.

Deliverable: A scored rubric and a fixed hour allocation for the rest of the week.

Day 2 — Largest gap: find the boundary rather than the subject

  • Split the weakest area into named sub-skills and rate each separately. For coding those are restating the problem, choosing the structure, stating the invariant, turning the invariant into loop bounds, handling empty and single-element input, and accounting for complexity out loud.
  • Attempt three items positioned just above where the rating drops off, and for each write the first move you failed to make.
  • Re-attempt one of them from blank four hours later with nothing open.

Deliverable: A sub-skill map with the two blocking sub-skills circled.

Day 3 — Drill the blocking sub-skill by repeating the shape

  • Do eight short repetitions of the same shape rather than eight different problems, so what gets practised is the pattern and not the puzzle.
  • State the rule you now hold in one sentence, then test it against a case built to break it, a sliding window over an array containing negative values, or a cache-aside read path whose invalidation message is dropped.
  • Have someone else read your one-sentence rule and find the precondition you left out.

Deliverable: One rule statement with its preconditions attached and one counterexample that would have caught the incomplete version.

Day 4 — Second gap, plus maintenance on the strongest area

  • Run the same sub-skill decomposition on the second-largest gap in half the time.
  • Spend twenty-five timed minutes on the block you scored highest, choosing the hardest item you can still finish rather than a warm-up.
  • Write whether each area fails you on recall, on setup, or on execution, and set the fix accordingly: repetition for recall, a written checklist for setup, timed work for execution.

Deliverable: A second sub-skill map plus a one-line failure diagnosis for each area.

Day 5 — The gap that is not a skill

  • Record one technical and one behavioural answer, then count two things in the playback: seconds before your first clarifying question, and sentences you began without knowing where they would end.
  • Practise saying that you do not know, followed by how you would find out, without letting it soften into a guess, and practise stating a complexity or an estimate before being asked for it.
  • Redeliver one answer under a hard ninety-second cap, which forces structure ahead of detail.

Deliverable: Two recordings with a counted reduction in time-to-first-question.

Day 6 — Retest under day-one conditions

  • Sit the same 110-minute structure with new prompts of comparable difficulty and score it on the identical rubric.
  • For any block that did not move, change the method rather than adding hours: a block stuck at 1 usually means the practice was too varied, not too short.
  • Write down which single block you would still lose the offer on.

Deliverable: A second scored rubric placed beside the first, with one named remaining risk.

Day 7 — Full loop under interview conditions

  • Run a sixty-minute mock over the two blocks that moved least, with an interviewer briefed to interrupt and change direction mid-answer.
  • Write the recovery script for going blank: restate the question, state your assumption, name the first thing you would check.
  • Say every rule from the week aloud without reading it, and cut any you cannot state in a single sentence, since a rule you have to reconstruct mid-answer will not survive an interruption.

Deliverable: A one-page card holding the recovery script and only the rules you could state from memory.

The estimate and the day you knew

A slipped date is only a bad story if you sat on it. What matters is what you believed when you gave the number, the signal that told you it was wrong, how many days passed before you said so, and what you cut rather than asking for more time. Scope you defended counts as much as scope you dropped.

Can you explain your experience with hardware bringup and communication between FPGAs and softcores?

Medium · behavioural and engineering judgement

Approach

  1. Name the disagreement and how you resolved it with evidence.
  2. Pick a story where you made the decision, not one where you watched it.
  3. Close with what you would do differently, concretely.

Follow-up

  • What would you do differently if you ran that again?
  • How did you know your change caused the improvement?

Unblock an engineer on a job run that finished twice

Easy · mentoring · fencing tokens · lease expiry · debugging method

An engineer two weeks into the team brings you a job_run row showing status succeeded with an exit_code written by a worker declared dead ten minutes earlier; the retry attempt also shows succeeded. They have spent a day adding logging and are no closer. You have twenty minutes and you do not want to take the keyboard. Describe how you unblock someone: the question you ask first, what you let them find themselves, the concept you name and when, and how you check the next day that they own the fix rather than having watched you produce it.

Approach

  1. Ask what they expect rather than what they see: which statement set status to succeeded, and what did it check before writing? That question points directly at the update's WHERE clause, which is where the answer lives, and it costs them nothing to answer, so it does not read as a test.
  2. Let them build the timeline themselves from the row: queued_at, started_at, leased_until, finished_at and worker_id, on both the original run and the retry. Two different worker_ids with a lease expiry between them tells the whole story, and they will see it before you say it.
  3. Name the concept once the evidence has earned it. A lease bounds time; it does not prevent a write. The store has to reject a stale writer, which means the update carries a fencing token the row compares — update job_run set status = 'succeeded' where run_id = $1 and lease_token = $2 and status = 'running' — and a long garbage-collection pause or a brief partition is enough to produce what they are looking at.
  4. Point at the second, less obvious half and let them decide it: 'lost' exists in the status enum precisely so a run whose worker vanished is not recorded as failed, because failed asserts an outcome nobody observed and the system then bills and retries on that assertion. Ask them what these two rows should have said.
  5. Leave them with the next step rather than the patch — a test that kills the first worker after the sandbox exits and before the row is written — and say when you are available again, so the offer is real rather than polite.
  6. Check ownership the next day by what they produced, not by asking if it went well: a test that reproduces the window proves they understood it; a test that only asserts the new WHERE clause proves they copied it. Ask them to explain it to a third person and listen for whether the explanation is theirs.

Follow-up

  • They propose a longer lease instead of a token. What do you say, and what breaks when legitimate runs last thirty minutes?
  • How can you tell whether your explanation landed or they simply deferred to you?
  • The same engineer hits a variant of this next month. What did you fail to teach the first time?

Estimate a tenant-leading index migration you have never run

Hard · estimation · online migration · index builds · uncertainty

Someone needs a date. usage_event carries an index on (occurred_at) and needs (tenant_id, occurred_at); the largest tenant holds roughly a hundred times the median tenant's rows, the table is partitioned daily with years of retention, and you have never run a migration on a table this large. Give an estimate you would defend: how you decompose the work, the two or three numbers you would go and measure first, the range and confidence you state, and what you commit to when the person asking needs a single date today.

Approach

  1. Refuse the bare number and then give one anyway, in the form that is actually useful: a range plus the measurement that collapses it. 'Four to eleven days; one afternoon building this index on a restored copy of the largest partition takes that to within a day' is an answer, while 'it depends' is not.
  2. Decompose by failure mode rather than into equal chunks, because that is where estimates go wrong. On a partitioned parent you create the index ON ONLY the parent, build each partition's index with CREATE INDEX CONCURRENTLY, then ALTER INDEX ... ATTACH PARTITION, at which point the parent index becomes valid. CONCURRENTLY does not block writes but scans each partition twice, waits out older transactions, cannot run inside a transaction block, and on failure leaves an invalid index you must drop concurrently and retry.
  3. Name the two unknowns that dominate and price them: build time on one restored partition of realistic size, and whether the planner actually chooses the new index for the skewed tenant, since selectivity for a tenant holding most of the rows is a different question from selectivity for the median tenant. Both are half-day measurements against a replica, and both are cheaper than being wrong by a week.
  4. State the assumptions the range is conditional on, because that is what makes a slip a re-estimate instead of a credibility event: no partition above a stated row count, one concurrent build at a time so it does not compete with ingest for I/O, and an ingest backlog that can absorb the added write amplification while both indexes exist.
  5. Budget the step nobody budgets: verification and the old index's removal. Dropping the old index is fast, but deciding it is safe to drop means confirming no plan still uses it, and that confirmation waits on real traffic across a full weekly cycle rather than on your patience.
  6. Answer the single-date request honestly. Commit to a date for the first checkpoint — the measured build number from the replica — and to re-estimating on that date, and say plainly what you are not committing to yet. A date with a scheduled re-estimate is worth more to the asker than a confident wrong one, and you should say why in those words.

Follow-up

  • The concurrent build fails half way through the largest partition. What is the state of the database and what do you do next?
  • Your estimate slips by sixty percent. Which assumption broke, and at what point would you have known?
  • The person asking needs the date for a customer commitment. Does your answer change?