Interview guides · Appian

Appian Software Engineer Interview Questions & Guide 2026

Concurrency drills for Appian software engineer prep: races, lock ordering, and what a check-then-act sequence assumes.

The 60-second brief

As a Software Engineer at Appian, you work on the company's mission to provide AI-powered process automation for mission-critical enterprise work. You will be responsible for building, scaling, and maintaining the foundational layers of Appian's platform, which affects how global organizations automate complex processes and manage enterprise-grade orchestration.

For a design discussion, a catalogue of architectures is worth less than the ability to turn a vague requirement into a data model and an API contract. A box diagram with no schema under it collapses at the first follow-up question.

Focus areas

Make every write idempotent under client retries
Scope every query and cache key by tenant
Build at-least-once pipelines with explicit deduplication horizons

Overview

This role is not just about writing code; it is about solving systemic challenges at scale. You will work within highly collaborative, cross-functional teams to design features of increasing sophistication, utilizing modern AI tooling to accelerate development. Whether you are improving the foundational platform, enhancing AI capabilities, or building developer tooling, your work directly influences the speed and reliability of the Appian platform.

You can expect to work in a fast-paced environment where technical precision and code quality are paramount. Appian values "Intensity" and "Excellence," meaning you will be challenged to solve real-world problems that require deep analytical thinking, robust architectural design, and a commitment to continuous learning.

The Appian interview process

Appian candidates report 4 rounds · ≈ 3-5 weeks. The stages below are what candidates describe, not a published process.

Recruiter Screening Call

Half of this call is the part candidates treat as small talk: start date, notice period, work authorisation and its timing, location and time zone, on-call, and the number. Those are what kill offers late, after several engineers have each spent a day. Surfacing a hard constraint now costs you nothing and occasionally buys you something, since a loop compressed to fit a competing deadline can usually only be arranged if it is asked for early. The common failure is deflecting the compensation question twice, then discovering at offer stage that the band never reached your number.

What to demonstrate

Whether your hard constraints are compatible with the role before a loop gets booked: earliest start, notice period, what authorisation you hold and when it needs action, days on site, willingness to carry a pager
Whether you give a compensation range with something behind it, such as current total compensation or a competing timeline, rather than leaving the band untested
Whether your stated timeline is real, since a competing deadline raised now is something scheduling can sometimes work around and the same deadline raised at offer stage usually is not

How to prepare

Write each constraint down in one line before the call and state them as facts rather than negotiating them live under a question you were not expecting
Set your range from two or three current data points for that level and location, and name the structure you are quoting in, so the number is comparable to the one they are holding
If another process is running, say where it stands and by when, and ask directly whether this loop can be scheduled inside that window

Technical Assessments

Most of the time lost in this format is not lost to thinking. It goes to a standard-library call you half-remember, an off-by-one in a loop bound, and a debugging loop that mutates code at random until something passes. When output is wrong, stop re-reading the whole function: take the smallest input that reproduces it and walk the state through by hand, printing intermediates if the environment allows. Guessing at a fix without a failing case you understand is how a five-minute bug becomes twenty, and the clock does not pause while you do it.

What to demonstrate

Whether you reach the right structure without a detour, and can write it from memory rather than only recall that one exists
Whether overflow is considered where the language has fixed-width integers, since a signed 32-bit value stops at 2,147,483,647 and then wraps in Java, is undefined behaviour in C++, and does not arise in Python, whose integers grow instead
Whether recursion depth is treated as a constraint on large inputs, given that CPython's default limit is 1000 frames and a deep recursion can exhaust the stack in any language where an iterative version would not
Whether a failing case is isolated and explained before any edit is made to the code

How to prepare

From an empty file and with no references open, implement the pieces you lean on most: a heap push and pop, an iterative DFS with an explicit stack, and a binary search whose midpoint is written lo + (hi - lo) / 2, which avoids the overflow that (lo + hi) / 2 can hit in a fixed-width integer type
Time yourself on the ten library calls you look up most, such as sorting with a custom comparator, splitting and joining strings, and finding the next key at or above a value in an ordered map, until the lookup is gone
Take a solution you know is broken and, before touching it, write one sentence naming the input, the expected value and the actual value. Repeat until you do it without deciding to.

Super Day

A day like this is several different games in a row, and the expensive mistake is carrying the previous one into the next room. Coding rewards narrow precision and finishing inside a timer. Design rewards breadth, stated assumptions and naming what you are deliberately not building. Behavioural rewards specificity about people and decisions. Candidates who over-engineer a coding problem they were supposed to finish, or who start sketching class hierarchies before anyone has agreed what the system has to do, are usually still playing the last round. Between rooms, name out loud which game the next one is.

What to demonstrate

Whether the coding round ends with something that runs and has been traced against a degenerate input, rather than an extensible design that was never finished
Whether a design discussion opens by agreeing on traffic shape, read-to-write ratio and what is allowed to be stale, instead of proceeding from an architecture you arrived with
Whether a behavioural answer names a person, a disagreement and what you did about it, rather than describing the system the story happened inside
Whether the opening habits still appear late in the day: restating the problem, asking for constraints, saying the plan before typing

How to prepare

Book three mocks of different types back to back on one afternoon and ask each interviewer afterwards which round you answered in the wrong mode
Write a three-line opening script per round type — coding: restate, name the approach and its cost, then type; design: ask for scale, read-write mix and what must not break; behavioural: name the person, the stakes and the decision — and run it off a card so the switch is mechanical rather than remembered
Practise coding with a timer you do not extend, stopping when it stops, so the trained reflex is to finish a correct solution rather than to keep improving one

Team Meetings

You cannot drill a format you do not know, so put the preparation into material that travels. Three pieces of your own work, each rehearsed until you can take a follow-up you did not anticipate, will carry a conversation or a code walkthrough equally well. Specificity is what separates that from filler. A number needs its definition before it means anything: a p99 is over some window and measured at some hop, and a server-side figure excludes the queueing and network time a client would see. The number you cannot qualify is the one to leave out.

What to demonstrate

Whether your examples carry detail only someone who did the work would hold, such as what the binding constraint actually was, which alternative you rejected and why it was worse, and what you measured on each side of the change
Whether a number survives one follow-up, meaning you can say what it was measured over and whether it moved because of your change or merely alongside it
Whether a failure is described with the specific change that followed it, rather than a lesson stated in general terms
Whether your part in a team effort is stated accurately, including what other people did

How to prepare

Write a page on each of three projects covering the constraint, the option you rejected, the measurement before and after, and what went wrong. Cut any line you cannot take a follow-up on, since you are writing the parts you will be pressed on rather than a summary.
Recover the real figures while you still have access: request volume, data size, latency with its percentile and window, team size, timeline. Note where each came from, whether a dashboard, a design document or memory, and mark the estimates so you can say which they are out loud.
Take your weakest project story to someone who works in a different area and have them ask why four times in succession. The point where you run out of answer is the part to go and re-read before the round.

Where candidates lose points

Checking a quota with a select and then writing

Under read-committed isolation, two concurrent transactions both observe a count below the limit and both insert, so the limit is exceeded by exactly the concurrency. Repeatable read does not rescue it either: it provides a stable snapshot, and this is write skew, which snapshot isolation permits by design. The options are serialisable isolation, which detects the conflict and aborts one transaction with a serialisation failure and therefore obliges the caller to retry; a single statement with the predicate inside the write; or a constraint that makes the surplus insert fail outright. The reason this pattern survives review is that it is correct in every test that runs one request at a time.

One shared connection pool for every tenant and every query class

A single tenant with a large table and a missing index can occupy every connection with slow queries, and every other tenant then waits in connection acquisition -- a queue invisible in database metrics, because the database itself looks healthy while the application starves. Containment is bulkheads: separate pools or per-tenant concurrency caps for interactive requests, background jobs and exports, a statement timeout low enough that a pathological query dies before it accumulates, and an idle-in-transaction timeout so a stuck client cannot pin a connection and its locks indefinitely. One caveat worth knowing in advance: if a transaction-pooling proxy sits in front of the database, session-scoped behaviour changes, so session-level advisory locks and settings applied outside a transaction do not survive the way they do on a direct connection.

Assuming the input fits in memory

Ask how large the input is in bytes before committing to an in-memory algorithm; beyond that point the options are a single streaming pass, an external sort with bounded buffers, or a sketch that trades exactness for constant memory. An algorithm that assumes random access to the whole input is a different algorithm from one that sees each element once.

Naming no test cases at all

State what you would test before being asked: empty input, a single element, all elements equal, the maximum permitted size, and the input that exercises the branch you just wrote. It costs thirty seconds and is much of what separates someone who has shipped code from someone who has only solved puzzles.

Questions & practice

Find the first and last position of an element in a sorted array.

Medium · data structures and algorithms

Approach

Choose the data structure from the access pattern, not from familiarity.
Walk one small example through your approach before writing the whole thing.
Name the brute-force solution and its complexity before improving on it.

Follow-up

What is the worst case, and how likely is it on real data?
How does this change if the input no longer fits in memory?

Solve a graph traversal problem (e.g., number of islands or finding paths in a tree).

Medium · data structures and algorithms

Approach

State the target complexity and say which constraint rules the naive version out.
Name the brute-force solution and its complexity before improving on it.
Restate the input: its shape, its size, and what is guaranteed about it.

Follow-up

Which test case would catch an off-by-one here?
How does this change if the input no longer fits in memory?

Implement a function to reverse a string.

Medium · data structures and algorithms

Approach

Walk one small example through your approach before writing the whole thing.
State the target complexity and say which constraint rules the naive version out.
Restate the input: its shape, its size, and what is guaranteed about it.

Follow-up

How does this change if the input no longer fits in memory?
What is the worst case, and how likely is it on real data?

Given a list of intervals, return the set of intervals after inserting a new one.

Medium · data structures and algorithms

Approach

State the target complexity and say which constraint rules the naive version out.
Restate the input: its shape, its size, and what is guaranteed about it.
Choose the data structure from the access pattern, not from familiarity.

Follow-up

How does this change if the input no longer fits in memory?
Which test case would catch an off-by-one here?

Seal an hour under late data with bounded memory

Hard · watermarks · late-data · quantile-sketch · conditional-write

Metering ingest reads 256 partitions at 10,000 to 40,000 events/second. Events carry occurred_at and ingested_at, and during a producer replay the gap between them is hours. Seal each UTC hour once no more than 50 parts per million of that hour's eventual quantity can still arrive, using memory that does not grow with the size of the replay. Define the watermark, the lateness parameter and how you measure it, the structure holding open hours, and the write that performs the seal. State what an idle partition does to your watermark.

Approach

Two clocks, two jobs. Bucket by occurred_at, because that is the hour the customer is billed for, and advance the watermark on ingested_at, because that is what the fold has consumed and what source_max_ingested_at records. Conflating them is what makes late data invisible.
The global watermark is the min over partitions of each partition's committed ingested_at, not the max: the fold is trustworthy only as far as the slowest partition. The consequence is that one idle partition pins the watermark forever and nothing seals, so an idle partition must promote its watermark to wall clock after a stated idle timeout, and that timeout becomes a correctness parameter, because a partition that is slow rather than idle gets sealed past.
Choose the lateness L from the measured distribution of ingested_at - occurred_at, weighted by quantity rather than by event count. The target is 50 ppm of the hour's quantity, and a replay is rare in events while carrying disproportionate mass, so an event-weighted quantile picks an L that is comfortably wrong at exactly the moment it matters.
Measure that quantile in bounded memory. A Greenwald-Khanna summary gives epsilon-approximate quantiles in O((1/epsilon) log(epsilon n)) space; a t-digest costs more per merge but has relative error that tightens at the tails, which is the half of the distribution you are reading at p99.99. Keep a separate summary per tenant class, because one tenant's batch importer is not the population.
Hold open hours in a min-heap keyed by hour_start. When the watermark advances, pop every hour with hour_end + L < W and seal it: O(log H_open) per advance and O(1) amortised per event to touch its bucket. Memory is open hours multiplied by distinct (tenant, workspace, sku) keys, so cap the number of simultaneously open hours and spill the oldest into usage_rollup_hourly as status='open' with a revision bump. While an hour is open the row is upsertable, so the store is your overflow.
The seal itself is a conditional write: update ... set status='sealed', sealed_at=now() where status='open' returning .... Two sealers race on every restart, and the loser must see zero rows and stop rather than write a second value. After the seal, an event for that hour is not an upsert but an adjustment, and source_max_ingested_at is what proves it arrived afterwards.

Worked solution (40 min)

Replay a day of events with a synthetic lateness distribution: 99.9% under two minutes, plus a 0.05% tail at four to six hours that carries 3% of total quantity.
Compute the p99.99 lateness two ways, event-weighted and quantity-weighted, and put the two numbers side by side.
Implement the min-heap of open hours with the watermark as the min over 256 partitions, then stall one partition for 20 minutes and observe what seals.
Set the idle-partition timeout to 60 seconds, repeat the stall, and measure how much quantity arrives after the seal.
Attempt the seal from two workers at once and confirm the conditional update lets exactly one through.

Expected result: The quantity-weighted p99.99 is hours larger than the event-weighted one. Choosing L from the event-weighted number lets roughly the tail's 3% of quantity land after the seal, 600 times the 50 ppm target. With the min watermark and no idle timeout, the stalled partition blocks all sealing; with a 60-second timeout, the stall is sealed past and its events arrive late.

Verify it yourself

Post-seal quantity as a fraction of the hour's total is at or below 50 ppm at the chosen L, measured rather than assumed.
The second sealer's update reports zero rows affected and writes nothing.
Heap size equals the number of open hours and does not grow with the replay's event count.

Follow-up

A replay starts during the sealing window for a period you are about to close. What do you do, and what is the customer-visible consequence of each option?
Your measured quantity-weighted p99.99 lateness is six hours and the invoice must be issued at 02:00 UTC on the first. How do you reconcile those two numbers?
How would you detect that L has drifted before it costs you an hour's quantity?

Find the join that inflates every invoice total

Medium · join fan-out · aggregation grain · sql correctness

invoice_line_item holds line_id, invoice_id, tenant_id, sku, rate_tier, quantity, unit_price_micros, amount_minor (bigint), currency, kind, voided_at. invoice_payment_attempt holds attempt_id, invoice_id, tenant_id, amount_minor, status (succeeded, failed, pending), created_at, and an invoice has many attempts. A finance report runs select i.invoice_id, sum(l.amount_minor), count(p.attempt_id) from invoice i join invoice_line_item l using (invoice_id) join invoice_payment_attempt p using (invoice_id) group by 1 and the totals are wrong. Say precisely what the sum now equals, and write a version that is also correct for invoices with zero attempts.

Approach

Compute what the query actually returns before fixing it. The two joins form a Cartesian product per invoice, so each line row repeats once per attempt row: sum(l.amount_minor) is the true total multiplied by the attempt count, and count(p.attempt_id) is attempts times lines. Three lines and two attempts report double the money and six attempts.
Reject the reflex repair. count(distinct p.attempt_id) does fix the count, because attempt_id is unique. sum(distinct l.amount_minor) does not fix the sum, because two legitimate lines with equal amounts collapse into one. DISTINCT inside an aggregate deduplicates values, not rows, and the difference stays invisible until two lines happen to match.
Aggregate each branch to invoice grain before joining: one CTE summing lines by invoice_id, one counting attempts by invoice_id, then join the two results. A LATERAL subquery per invoice is equivalent and sometimes plans better when the outer set is small. Either way every aggregate stays at the grain it was defined at.
Keep invoices with no attempts by making the attempt branch a LEFT JOIN with coalesce(attempt_count, 0). An inner join here silently drops every unpaid invoice, which is usually the exact population finance is asking about.
Push each filter to its own grain: where l.voided_at is null belongs inside the line CTE, not the outer query, or it would also filter the attempt branch through the join. Put the tenant predicate on both branches, since the denormalised tenant_id is what stops a wrong join crossing tenants.
Leave yourself a standing check: an invoice total is a function of its non-voided lines and of nothing about payments, so if changing the payment filter moves the money figure, the fan-out is back.

Worked solution (25 min)

Create one invoice with three lines of 1000, 1000 and 500 minor units and two payment attempts, then run the original query.
Confirm it reports 5000 and 6 rather than 2500 and 2.
Apply sum(distinct l.amount_minor) and confirm the total becomes 1500, which is worse rather than better.
Write the two-CTE version with a LEFT JOIN and coalesce, and confirm 2500 and 2.
Add a second invoice with lines and no attempts and confirm it still appears.

Expected result: The original sum equals the true line total multiplied by the number of payment attempts and the count equals attempts times lines; the corrected query pre-aggregates each branch to invoice grain in separate CTEs and LEFT JOINs them with coalesce, with voided lines excluded inside the line CTE and the tenant predicate applied to both branches.

Verify it yourself

The money total is unchanged by adding or removing payment attempts.
An invoice with zero attempts appears with its total and a zero count.
Two lines with identical amounts both contribute to the total.
Voiding a line changes the money figure and leaves the attempt count alone.

Follow-up

Add a third branch for credit notes applied to the invoice. Does the CTE shape still hold, and when would a single pass with filter (where ...) be better?
Over 500k invoices this report takes minutes. Which grain would you materialise, and how do you keep it correct when a line is voided?
The same report is needed per tenant per month. What index makes the line CTE cheap?

Explain why the metering dashboard scans every daily partition

Medium · indexing · partition pruning · sargability · tenant skew

usage_event is range-partitioned daily on ingested_at and holds tenant_id, workspace_id, environment, sku, quantity numeric(20,6), occurred_at and ingested_at. The only relevant index is on (occurred_at). A dashboard runs select sku, sum(quantity) from usage_event where tenant_id = $1 and date_trunc('hour', occurred_at) >= $2 and environment = 'production' group by sku, and EXPLAIN shows a sequential scan of every partition. Give each distinct reason, rewrite the predicate so an index can serve it, propose the index, and state the write cost its column order adds.

Approach

Separate the three causes rather than blaming one. First, date_trunc('hour', occurred_at) wraps the column, so the predicate is not sargable against a btree on the bare column. Second, pruning keys off ingested_at while the query constrains occurred_at, so no partition can be excluded. Third, even made sargable, (occurred_at) is not tenant-leading, so for one tenant among thousands the scan reads the whole time range and discards nearly all of it.
Rewrite the bound carefully, because the obvious rewrite is only conditionally equivalent. date_trunc('hour', x) >= $2 equals x >= $2 only when $2 is already hour-aligned; for an arbitrary $2 it means x >= date_trunc('hour', $2) + interval '1 hour'. Normalise the parameter in the caller and leave the column bare.
Restore pruning with a second, redundant predicate on the partition key: ingested_at >= $2 - interval '<late-data horizon>'. State both sides of it. It prunes to a handful of partitions, and it silently omits any event whose ingest lagged past that horizon, which is precisely what a producer replay produces. Either document the horizon as a stated bound, or partition on occurred_at and move the problem into the dedup window instead.
Propose (tenant_id, occurred_at) include (sku, quantity) per partition. A partial index where environment = 'production' mostly saves size rather than selectivity, since production dominates the three environments; take it if non-production is a meaningful share and skip it otherwise.
Price the write path honestly. At roughly 250M rows/day each extra index is another insert plus WAL per row, and a tenant-leading key scatters inserts across one hot leaf per active tenant instead of appending to a single rightmost leaf, so page dirtying and random I/O both rise. An INCLUDE payload widens every leaf entry and enlarges the index accordingly.
Add the index-only-scan caveat before someone reports it as a regression: on a freshly appended table the visibility map is not yet set for recent pages, so the INCLUDE columns still cost heap fetches until autovacuum has been through, and the newest hour is exactly the data the dashboard reads.

Follow-up

CREATE INDEX CONCURRENTLY is not supported on a partitioned parent. Give the sequence that gets this index onto 400 existing partitions without blocking ingest.
One tenant holds 200 times the median row count and the dashboard still times out for them with the index in place. What changes?
Should this read hit usage_rollup_hourly instead? State what that costs in freshness and what the watermark lets you promise.

Explain the difference between a linked list and an array.

Medium · system design and architecture

Approach

Fix the scope first: who calls this, how often, and what they do when it fails.
State the consistency you need, and where you are willing to be stale.
Name the read and write paths separately; they rarely have the same bottleneck.

Follow-up

What breaks first when traffic grows ten times?
How does this behave when that dependency is down for an hour?

Describe how you would handle data consistency and high availability in a system.

Medium · system design and architecture

Approach

Choose a partition key and say what query it makes expensive.
Name the failure you are designing for, then the recovery path.
State the consistency you need, and where you are willing to be stale.

Follow-up

How does this behave when that dependency is down for an hour?
What would you drop to keep the system up under load?

Design the batch ingest endpoint metering agents retry into

Hard · batch api · partial failure · deduplication

A customer-run agent posts usage events in batches of up to 1,000 to metering-ingest with a 30-second timeout and at-least-once retry of the whole batch. Each event carries event_id, idempotency_key, sku, quantity and occurred_at; the server adds ingested_at, and usage_event is partitioned daily on ingested_at with unique (ingested_day, tenant_id, idempotency_key). Design the endpoint: the request shape, what the response says when 900 events are new, 90 are duplicates and 10 are malformed, the status code, and the agent's algorithm on timeout. Then state the deduplication horizon and justify it against that unique constraint.

Approach

Fix the per-item outcome taxonomy first, because the status code follows from it: accepted, duplicate, and rejected with a permanent code. A duplicate is a success; reporting it as an error makes the agent either re-send revenue it already delivered or drop it.
Allow only permanent failures per item. A transient per-item failure inside a 200 invites the agent to discard that event, so anything transient escalates to a 5xx for the entire batch. A 200 is then a promise that every event not marked rejected is committed and durable.
Return 200 with a results array aligned by index and carrying the event id, so the agent can retry precisely the subset that needs it and quarantine the ten malformed events instead of hard-looping a poison batch forever. Cap the batch at 1,000 items and a byte size, with 413 beyond it and 429 with Retry-After for backpressure.
Deduplicate per event, never per batch: the agent may split, merge or reorder a retried batch, so a batch-level key matches nothing on the second attempt. The key is (tenant_id, idempotency_key), and the tenant comes from the resolved credential; a tenant id present in the body is compared against it, never trusted.
Size the horizon as a correctness parameter. The unique index includes the partition key, so it deduplicates only within one day: a retry that crosses midnight, or a replay run a week later, passes straight through it. A separate dedup store keyed (tenant_id, idempotency_key) with a TTL exceeding the agent's maximum retry window plus the longest replay you intend to support is what actually enforces the invariant, which makes its retention a correctness setting rather than a cost knob.
Order the commit against the response and the acknowledgement: commit then respond at the endpoint, and downstream commit the fold then acknowledge the message. Acknowledging first turns a crash into silently lost revenue with no error raised anywhere.

Worked solution (40 min)

Write the request body schema with the batch envelope and one event, and state which fields the server assigns rather than accepts.
Write the 200 response for the 900/90/10 case, showing three result entries, one of each outcome, with the rejected one carrying a permanent code.
Write the rule separating per-item rejection from whole-batch failure, and list which conditions fall on each side.
Compute the dedup horizon from the agent's retry window plus the replay window you support, and say where the dedup state lives and how it ages out.
Write the agent's pseudocode for timeout, 5xx, 429 and 200-with-rejections, four branches, and mark which branch may drop an event.
Trace the crash between commit and response, and between fold and acknowledgement, and say what each produces.

Expected result: A 200 with an index-aligned results array where duplicates count as success and rejections are permanent-only, transient problems escalated to a whole-batch 5xx, per-event deduplication keyed on (tenant_id, idempotency_key), and a published horizon larger than retry plus replay because the partitioned unique index only covers one day.

Verify it yourself

The agent can distinguish 'already counted' from 'never counted' for every event in the batch.
Exactly one branch of the agent's algorithm ever discards an event, and it is the permanent-rejection branch.
A retry crossing midnight is still deduplicated, and the mechanism named is not the unique index.
No crash point in the pipeline both commits work and loses it without an error.

Follow-up

The agent times out at 30 seconds having received nothing. What exactly does it do next, and what in your design makes that safe?
Ten events are rejected every hour for a week and nobody notices. What does the endpoint owe the customer beyond a per-item 4xx code?
A replay pushes 40 million events through this endpoint in an hour. Which part of your design degrades first?

Hourly rollups merge one hour and lose another

Easy · timezone · rollups · reconciliation

Reconciliation flags one tenant on one day. Summing usage_event.quantity by hour of occurred_at gives 24 non-empty hours, but usage_rollup_hourly holds 23 rows for that tenant, workspace and SKU, one of which carries roughly the sum of two adjacent hours. Other days reconcile exactly, and the affected date matches a civil-time transition. hour_start is documented as truncated to the hour in UTC. You have both tables, the rollup job source, and its runtime environment. Give an ordered checklist, the mechanism, and the correction path for a day that may already be sealed.

Approach

Bisect by dimension until one cell explains the whole difference: tenant, then day, then SKU, then hour. A defect confined to a single transition date already rules out deduplication and late arrival, both of which are indifferent to which hour an event lands in.
Read the truncation with its precondition stated: date_trunc on a timestamptz value is evaluated in the session TimeZone, not in UTC. If the job connects without pinning that setting, it inherits the server or container default.
Follow that to the collision: in a zone that observes daylight saving, two distinct UTC hours map to the same local wall-clock label at the autumn transition, so both fold into one key under the unique constraint on (tenant_id, workspace_id, sku, hour_start) and their quantities sum into one row. At the spring transition a label never occurs and the row is simply absent.
Confirm from data rather than from reading code: run the same aggregate twice, once with the session pinned to UTC and once with the job host zone, and check that the second reproduces the stored rollup exactly.
Fix at the source by pinning the connection to UTC explicitly, or by truncating on occurred_at AT TIME ZONE 'UTC', rather than relying on a default that differs between a developer machine, CI and production.
Correct according to status, not convenience: an open hour is recomputed with revision incremented, a sealed hour is frozen and the difference becomes an adjustment line on the next invoice with voided_by_line_id pointing at the line it reverses.

Follow-up

The same job also emits a daily figure for a dashboard. Why can a correct hourly rollup still produce a wrong day, and what does the tenant's billing timezone have to do with it?
How would you detect this class automatically rather than waiting for reconciliation, given that it only manifests twice a year per zone?

Suggested practice checklist

Roughly ninety minutes on weeknights with one longer weekend block. The plan cuts scope rather than compressing everything, on the assumption that one thing finished per night beats four half-started.

Day 1 — Fix the scope and take a cold baseline

Read the role description and write the three things the loop will almost certainly test, then write an explicit not-doing list and keep it visible all week.
Take one twenty-five-minute coding problem and one fifteen-minute design prompt cold, and write the single sentence naming what blocked each, because those two sentences decide where the remaining evenings go.
Set the week's rule: one thing finished every night, including the night you only have forty minutes.

Deliverable: A one-page scope with a not-doing list and two cold attempts, each carrying one sentence on what blocked it.

Day 2 — One pattern, written three times from blank

Choose the single pattern most likely to appear in your loop and write it three times from an empty file rather than editing the previous attempt.
On the third pass, write the invariant as a comment before the loop body and the complexity before the first line of code.
Stop at ninety minutes even if the third version is imperfect, and write the one thing you would fix given another hour.

Deliverable: Three independent implementations of the same pattern plus a note on what changed between them.

Day 3 — One design, only to the depth you can defend

Take one system shape and go only as far as requirements, interface and data model, refusing to draw a box you could not survive a follow-up about.
Attach one number to each non-functional requirement, deriving it rather than asserting it, and write the assumption the number rests on.
Write the one tradeoff you are choosing against and the observation that would make you reverse it.

Deliverable: One design at interface-and-schema depth with derived numbers and one written reversible tradeoff.

Day 4 — Only the fundamentals you will have to defend

Write, in under two hundred words each, the answers to the two questions that follow almost any implementation: why this structure and not the obvious alternative, and what happens to this code at a hundred times the input.
Write what an index actually costs: faster lookups on the indexed columns against a write that now maintains a second structure, plus the cases where the planner declines to use it anyway, low selectivity, or a predicate wrapping the column in a function.
Delete any answer you cannot deliver aloud in under a minute, since an answer that needs reading is not an answer you have.

Deliverable: Three written answers, each under two hundred words and each timed aloud.

Day 5 — Your own work, timed

Write a ninety-second and a four-minute version of your main project and time both aloud rather than reading them.
Prepare the two follow-ups that always come: what you would do differently, and how you knew it worked.
Put one number in the first sentence and be ready to say exactly where it came from and what it excludes.

Deliverable: Two timed narratives with one defensible number in the opening line.

Day 6 — The one full rehearsal, in the weekend block

Run a sixty-minute mock covering a coding round and a design round in one sitting with no break, because sustained attention is the thing evenings have not trained.
Immediately afterwards, and before hearing any feedback, write the three moments you lost the thread.
Spend the rest of the block only on those three moments, and on nothing you merely feel shaky about.

Deliverable: Mock notes naming three failure moments with a specific fix written under each.

Day 7 — Taper

Write the twenty-minute warm-up you will actually do on the morning: one problem you can already solve from a blank file, one design you can narrate, and nothing you have never seen.
Re-read only your own notes from this week and open no new material.
Write the logistics down: the editor or shared document you will be working in, whether execution and lookups are permitted, and the sentence you will use when you do not know something.

Deliverable: A one-page card holding the design structure, the project numbers, and the logistics.

The estimate and the day you knew

A slipped date is only a bad story if you sat on it. What matters is what you believed when you gave the number, the signal that told you it was wrong, how many days passed before you said so, and what you cut rather than asking for more time. Scope you defended counts as much as scope you dropped.

Why do you want to work at Appian?

Medium · behavioural and engineering judgement

Approach

Close with what you would do differently, concretely.
Give the blast radius: what could have broken, and what you measured.
Name the disagreement and how you resolved it with evidence.

Follow-up

What did you decide not to do, and why?
What would you do differently if you ran that again?

Describe a situation where you had a disagreement with a coworker. What was the outcome?

Medium · behavioural and engineering judgement

Approach

Close with what you would do differently, concretely.
State the situation in two sentences and spend the rest on the reasoning.
Give the blast radius: what could have broken, and what you measured.

Follow-up

How did you know your change caused the improvement?
What would you do differently if you ran that again?

Estimate a tenant-leading index migration you have never run

Hard · estimation · online migration · index builds · uncertainty

Someone needs a date. usage_event carries an index on (occurred_at) and needs (tenant_id, occurred_at); the largest tenant holds roughly a hundred times the median tenant's rows, the table is partitioned daily with years of retention, and you have never run a migration on a table this large. Give an estimate you would defend: how you decompose the work, the two or three numbers you would go and measure first, the range and confidence you state, and what you commit to when the person asking needs a single date today.

Approach

Refuse the bare number and then give one anyway, in the form that is actually useful: a range plus the measurement that collapses it. 'Four to eleven days; one afternoon building this index on a restored copy of the largest partition takes that to within a day' is an answer, while 'it depends' is not.
Decompose by failure mode rather than into equal chunks, because that is where estimates go wrong. On a partitioned parent you create the index ON ONLY the parent, build each partition's index with CREATE INDEX CONCURRENTLY, then ALTER INDEX ... ATTACH PARTITION, at which point the parent index becomes valid. CONCURRENTLY does not block writes but scans each partition twice, waits out older transactions, cannot run inside a transaction block, and on failure leaves an invalid index you must drop concurrently and retry.
Name the two unknowns that dominate and price them: build time on one restored partition of realistic size, and whether the planner actually chooses the new index for the skewed tenant, since selectivity for a tenant holding most of the rows is a different question from selectivity for the median tenant. Both are half-day measurements against a replica, and both are cheaper than being wrong by a week.
State the assumptions the range is conditional on, because that is what makes a slip a re-estimate instead of a credibility event: no partition above a stated row count, one concurrent build at a time so it does not compete with ingest for I/O, and an ingest backlog that can absorb the added write amplification while both indexes exist.
Budget the step nobody budgets: verification and the old index's removal. Dropping the old index is fast, but deciding it is safe to drop means confirming no plan still uses it, and that confirmation waits on real traffic across a full weekly cycle rather than on your patience.
Answer the single-date request honestly. Commit to a date for the first checkpoint — the measured build number from the replica — and to re-estimating on that date, and say plainly what you are not committing to yet. A date with a scheduled re-estimate is worth more to the asker than a confident wrong one, and you should say why in those words.

Follow-up

The concurrent build fails half way through the largest partition. What is the state of the database and what do you do next?
Your estimate slips by sixty percent. Which assumption broke, and at what point would you have known?
The person asking needs the date for a customer commitment. Does your answer change?