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AIStrata Software Engineer Interview Questions & Guide 2026

Software engineer interview prep for AIStrata: original coding, system design and debugging practice, each with a worked solution.

The 60-second brief

As a Software Engineer at AIStrata, you build scalable solutions that underpin the company's technology. You will contribute to a diverse range of initiatives, from developing robust enterprise applications using Microsoft C#.Net to architecting secure, decentralized solutions via Blockchain technologies. Your work affects how AIStrata processes data and delivers value to its global user base.

State every complexity claim with the assumption sitting under it. Hash lookup is O(1) on average and only for a hash that spreads your actual keys; comparison-based sorting cannot beat n log n, though counting or radix sort can when the keys are bounded integers.

Focus areas

  • Scope every query and cache key by tenant
  • Bound blast radius with per-tenant concurrency limits
  • Build at-least-once pipelines with explicit deduplication horizons

Overview

This role is designed for engineers who thrive on technical complexity and are eager to work across a broad stack including Java, PHP, and Python. Whether you are optimizing backend services or integrating complex blockchain protocols, your output will be foundational to AIStrata’s mission. The role suits engineers who treat code as a craft and are committed to building resilient, maintainable, and high-performance systems.

The AIStrata interview process

AIStrata candidates report 4 rounds · ≈ 3-5 weeks. The stages below are what candidates describe, not a published process.

Technical Screening

Input bounds are the part of the prompt most often skimmed, and they usually contain the answer. They tell you which complexity class is admissible, which narrows the search before you have thought about the problem itself. As a rough planning figure, a compiled language does on the order of 10^8 simple operations per second and an interpreted one roughly an order of magnitude less. So n up to about twenty admits enumerating subsets, a few thousand admits a quadratic pass, and a million admits neither: you need near-linear, or linear with a log factor. If the bounds are missing, ask for them.

What to demonstrate

  • Whether the approach is justified by the stated input size rather than by whichever pattern you recognised first
  • Whether you ask about the properties that change the algorithm: whether the input arrives sorted, whether duplicates occur, whether values are bounded integers, whether it all fits in memory
  • Whether you can name the bottleneck in your own solution and what would remove it, even when you deliberately leave it in place
  • Whether a claimed speedup is real, since memoising a recursion only helps when subproblems genuinely overlap and the state can be keyed cheaply

How to prepare

  • For each algorithm you rely on, write down the largest n it handles in roughly a second, then check two of those figures by timing them in the language you will actually type in
  • For two weeks, write one line naming your target complexity and the bound that justifies it before you write any code, then compare that line with what you ended up submitting
  • Practise the conversion backwards: given a required O(n log n), list the mechanisms that get you there (sorting, a heap, an ordered map, divide and conquer) and choose by what the problem needs to query, not by what you used last

Technical Deep-Dives

What this round decides is narrow: whether you can produce code that runs and is correct on inputs nobody showed you. An elegant solution that does not compile scores below a plain one that does, so write a correct brute force first, say out loud that you know its cost, and improve it with the working version still on screen. What separates strong answers is who finds the broken case. Trace your own code against an empty input, a single element, and duplicate keys before you say you are finished, because being told is far more expensive than noticing.

What to demonstrate

  • Whether degenerate inputs get checked without being asked for: an empty collection, one element, every element equal, and the extreme value the input type allows
  • Whether the complexity you state matches the code you actually wrote, including a sort or a copy sitting inside a loop
  • Whether the finished answer is verified against the worked examples before you call it done, rather than assumed correct because the code reads correctly

How to prepare

  • Take five problems you have already solved and, without running anything, write down what each returns for empty input, a single element, and all-duplicates. Then run them and count how many you predicted wrong.
  • Drill the brute force as its own skill: on ten problems, write only the obviously-correct slow version and time how long it takes to get it passing. If that is more than a few minutes, that is what to practise, not the optimal version.
  • Add a fixed last step before you submit anything, reading only the loop bounds and the initial value of each accumulator, which is where most off-by-one errors live

Architectural Discussions

You cannot drill a format you do not know, so put the preparation into material that travels. Three pieces of your own work, each rehearsed until you can take a follow-up you did not anticipate, will carry a conversation or a code walkthrough equally well. Specificity is what separates that from filler. A number needs its definition before it means anything: a p99 is over some window and measured at some hop, and a server-side figure excludes the queueing and network time a client would see. The number you cannot qualify is the one to leave out.

What to demonstrate

  • Whether your examples carry detail only someone who did the work would hold, such as what the binding constraint actually was, which alternative you rejected and why it was worse, and what you measured on each side of the change
  • Whether a number survives one follow-up, meaning you can say what it was measured over and whether it moved because of your change or merely alongside it
  • Whether a failure is described with the specific change that followed it, rather than a lesson stated in general terms
  • Whether your part in a team effort is stated accurately, including what other people did

How to prepare

  • Write a page on each of three projects covering the constraint, the option you rejected, the measurement before and after, and what went wrong. Cut any line you cannot take a follow-up on, since you are writing the parts you will be pressed on rather than a summary.
  • Recover the real figures while you still have access: request volume, data size, latency with its percentile and window, team size, timeline. Note where each came from, whether a dashboard, a design document or memory, and mark the estimates so you can say which they are out loud.
  • Take your weakest project story to someone who works in a different area and have them ask why four times in succession. The point where you run out of answer is the part to go and re-read before the round.

Final Evaluations

Where the day includes a partner from product, design or data, that conversation is weighted like the technical ones and prepared for least. They are deciding one thing: whether having you in the room makes their decisions cheaper. That means options with costs attached, not implementation detail and not "it depends". An estimate someone can plan against — a range, the assumption that would push it to the high end, and what you would drop to hit the low one — is worth more than a confident single number, which everyone present already knows is wrong.

What to demonstrate

  • Whether an estimate comes as a range with the assumption most likely to break it, and states what a specific scope cut would actually buy
  • Whether a technical constraint is handed over as a choice with consequences on their side, rather than as a verdict they have no standing to argue with
  • Whether you establish what decision is on the table before proposing anything
  • Whether risk is raised while it can still change the plan, with the trigger that would confirm it, instead of reported afterwards as a slip

How to prepare

  • Take a project that shipped late and write the two-sentence warning you could have given three weeks earlier, naming what you would have needed decided at that point
  • Rehearse one estimate out loud until it arrives in three parts: the range, the single assumption that would blow it, and the smallest thing you would cut to protect the date
  • Rewrite an objection you have actually made — the "we can't do that" version — as two options with their costs, so the choice ends up with the person who owns it

Where candidates lose points

Checking a quota with a select and then writing

Under read-committed isolation, two concurrent transactions both observe a count below the limit and both insert, so the limit is exceeded by exactly the concurrency. Repeatable read does not rescue it either: it provides a stable snapshot, and this is write skew, which snapshot isolation permits by design. The options are serialisable isolation, which detects the conflict and aborts one transaction with a serialisation failure and therefore obliges the caller to retry; a single statement with the predicate inside the write; or a constraint that makes the surplus insert fail outright. The reason this pattern survives review is that it is correct in every test that runs one request at a time.

Treating a timed-out write as a failed write

A timeout says the response did not arrive, not that the work did not happen; the server may well have committed and then lost the connection. Retrying a non-idempotent create after a timeout is the standard way to end up with two of something, and those duplicates land precisely when the system is already degraded and least able to absorb them. The discipline is to treat a timeout as unknown: either the write carries an idempotency key so the retry is safe by construction, or the client re-reads authoritative state before deciding what to do, and the interface says unknown rather than showing a failure that invites a second click.

Hardcoding to the sample inputs

Solve the stated problem rather than the two examples; special-casing a literal to make a sample pass is obvious immediately and reads as either a misunderstanding or an attempt to fake progress. If you genuinely cannot generalise yet, say which part is a stub and what would replace it.

A queue or buffer with no bound

Every producer-consumer boundary needs a capacity and a policy for reaching it: block the producer, shed load, or drop the oldest entry. Unbounded buffering converts a temporary slowdown into memory exhaustion and hides the backpressure signal that would have revealed the consumer was falling behind.

Questions & practice

How do you manage memory and garbage collection in a Java environment?

Medium · data structures and algorithms

Approach

  1. Name the brute-force solution and its complexity before improving on it.
  2. Restate the input: its shape, its size, and what is guaranteed about it.
  3. State the target complexity and say which constraint rules the naive version out.

Follow-up

  • What is the worst case, and how likely is it on real data?
  • How does this change if the input no longer fits in memory?

Describe the process of optimizing a PHP application for high concurrency.

Medium · data structures and algorithms

Approach

  1. Choose the data structure from the access pattern, not from familiarity.
  2. Name the brute-force solution and its complexity before improving on it.
  3. State the target complexity and say which constraint rules the naive version out.

Follow-up

  • How does this change if the input no longer fits in memory?
  • Which test case would catch an off-by-one here?

Explain the core differences between value types and reference types in C#.

Medium · data structures and algorithms

Approach

  1. Walk one small example through your approach before writing the whole thing.
  2. Choose the data structure from the access pattern, not from familiarity.
  3. State the target complexity and say which constraint rules the naive version out.

Follow-up

  • What is the worst case, and how likely is it on real data?
  • How does this change if the input no longer fits in memory?

How do you implement secure API authentication in a Python-based backend?

Medium · data structures and algorithms

Approach

  1. Restate the input: its shape, its size, and what is guaranteed about it.
  2. Walk one small example through your approach before writing the whole thing.
  3. Name the brute-force solution and its complexity before improving on it.

Follow-up

  • What is the worst case, and how likely is it on real data?
  • Which test case would catch an off-by-one here?

Schedule ordered webhook retries with a heap of subscription queues

Medium · heap · scheduling · backoff · head-of-line-blocking

Design the in-memory scheduler for webhook delivery. Up to 20 million rows sit in status pending or failed_retryable across 200,000 subscriptions, each row carrying next_attempt_at and attempt_count, and each endpoint having a circuit breaker. Deliveries for one subscription must be attempted in order, so at most one attempt per subscription may be in flight. Support due(now), complete(delivery, outcome) and insert(delivery) in O(log S), where S is the subscription count rather than the delivery count. Give the backoff formula you schedule retries with.

Approach

  1. Key the global heap by subscription, not by delivery. Each subscription owns a FIFO of its due deliveries in event order; the heap holds one entry per eligible subscription, keyed by its head's next_attempt_at. That is 200,000 heap entries instead of 20 million, and it makes the one-in-flight rule structural rather than a check somebody can forget.
  2. due(now): peek the minimum. If its key is in the future, sleep until then instead of spinning. Otherwise pop it, move the subscription into an in-flight set, and do not re-push it. A subscription absent from the heap cannot be dispatched twice, which is precisely how ordering is preserved.
  3. complete: on success, drop the head and re-push the subscription keyed by its new head, or leave it out when the queue empties. On a retryable failure, increment attempt_count and set next_attempt_at = now + uniform(0, min(cap, base * 2^attempt)), sampled uniformly across the whole interval. That is full jitter; deterministic backoff re-synchronises the herd you just created.
  4. Circuit breaker: park the subscription in a second heap keyed by its half-open time, so an endpoint dead for six hours costs one heap entry and zero attempts rather than consuming worker slots. Admit exactly one probe at half-open and close the breaker only on its success.
  5. Say the price of the ordering guarantee out loud. One in-flight attempt per subscription means an endpoint answering in 10 seconds drains at 0.1 deliveries/second however many workers you run, and its backlog grows until it recovers. If the customer does not need order, allow k in flight and document delivery as unordered; that is the trade, and it is a product decision.
  6. All three operations are O(log S) with O(S) resident heap memory and the queues themselves backed by the store. The database-backed equivalent is a partial index on (subscription_id, next_attempt_at) where status in ('pending','failed_retryable') claimed with FOR UPDATE SKIP LOCKED, and the write-back must be fenced on lease_token so a worker that stalled and resumed cannot overwrite a newer attempt.

Worked solution (30 min)

  1. Define the four structures explicitly: queues: subscription_id -> deque[delivery], ready: min-heap of (next_attempt_at, subscription_id), inflight: set[subscription_id], breaker: min-heap of (half_open_at, subscription_id).
  2. Write down the invariant you will assert after every operation: a subscription appears in at most one of ready, inflight and breaker, never in two.
  3. Implement due, complete and insert, then simulate 200,000 subscriptions with Zipf-distributed queue depths totalling 20 million deliveries.
  4. Add one endpoint that always times out after 10 seconds and one that always answers in 20 ms, then measure the fast endpoint's throughput with and without the per-endpoint breaker.
  5. Instrument heap size across the run.

Expected result: Heap size stays at or below 200,000 regardless of the 20 million deliveries. The fast endpoint's throughput is unaffected by the dead one once the breaker trips. The dead endpoint's deliveries accumulate in their own deque and cost exactly one heap entry.

Verify it yourself

  • The asserted invariant never fires under concurrent workers.
  • Replaying the same delivery set twice produces identical per-subscription ordering, even though the interleaving across subscriptions differs.
  • Replacing full jitter with fixed backoff makes retry attempts cluster visibly in a histogram of attempt timestamps.

Follow-up

  • One subscription has 4 million queued deliveries. What stops it from starving the other 199,999, and what does your heap look like under that load?
  • A customer requests redelivery of last Tuesday's events. Where do those rows enter your structure, and what keeps them from reordering live traffic?
  • The process restarts. How much state do you rebuild, and what stops every subscription from being attempted in the same second?

Paginate a tenant's delivery export without skipping rows

Easy · keyset pagination · indexing · multi-tenancy

A customer exports webhook_delivery: delivery_id (bigint identity), subscription_id, tenant_id, event_id, status, attempt_count, next_attempt_at, created_at, delivered_at, updated_at. The endpoint runs select ... where tenant_id = $1 order by created_at desc limit 100 offset $2, and customers report rows missing from exports taken while new deliveries are being inserted. Write the replacement query and the index that supports it, paging a tenant's deliveries newest first at constant cost per page. State why updated_at cannot be the cursor column.

Approach

  1. Name the defect precisely. OFFSET is a position in a result set that is recomputed on every request, so a row inserted ahead of the window shifts everything back by one and the next page starts after a row the client never received. Nothing errors and no identifier gap appears, so the loss is silent.
  2. Replace the position with a value predicate over a stable, unique, indexed ordering: where tenant_id = $1 and (created_at, delivery_id) < ($2, $3) order by created_at desc, delivery_id desc limit 100. The row comparison is load-bearing: created_at alone is not unique, so ties straddling a page boundary are dropped or repeated, which is the same bug in a smaller window.
  3. Index (tenant_id, created_at, delivery_id). PostgreSQL scans a btree in either direction, so an all-DESC ORDER BY is served by an ASC index read backwards and no DESC modifiers are needed; they only matter when the ORDER BY mixes directions. Confirm the plan has no Sort node above the index scan, or the LIMIT stops being an early exit.
  4. Price both forms: keyset is one index descent plus 100 adjacent leaf entries per page, constant regardless of depth, while OFFSET still produces and discards every skipped row, so page N costs time proportional to N times the page size and a deep page on a large table goes from milliseconds to seconds.
  5. Rule out updated_at as the cursor from the precondition, not from taste: a cursor column must never change value for a row already paged past. updated_at moves on every delivery attempt, so a row the client already emitted re-enters a later page and is exported twice. created_at and delivery_id are immutable, which is the whole qualification.

Worked solution (20 min)

  1. Load about 50k deliveries for one tenant, then walk them with the OFFSET query while a writer inserts 10 rows/second, collecting every returned delivery_id.
  2. Compare the distinct ids collected against the set of ids that existed when the walk started, and record the shortfall.
  3. Repeat the walk with the keyset query and confirm every pre-existing id is returned exactly once.
  4. Run explain (analyze, buffers) on page 1 and page 500 of each form and compare shared buffer hits.

Expected result: A keyset query using the row comparison (created_at, delivery_id) < ($2, $3) with order by created_at desc, delivery_id desc limit 100, backed by (tenant_id, created_at, delivery_id) scanned backwards; plus the statement that OFFSET drops rows under concurrent insert and costs time proportional to the offset, and that updated_at is disqualified because it mutates on retry.

Verify it yourself

  • Buffer counts for page 500 are the same order of magnitude as page 1.
  • Every id present before the walk is returned exactly once when only inserts run concurrently.
  • The query plan shows no Sort node above the index scan.
  • Two rows sharing a created_at value to the microsecond are both returned across the page boundary.

Follow-up

  • The client wants a snapshot as of one instant rather than a live tail. Compare a repeatable-read transaction held open, an added created_at <= $snapshot bound, and a materialised export table.
  • A retention job deletes deliveries older than 90 days. What does a client mid-walk see, and does keyset pagination help at all?
  • The customer wants to resume an export from yesterday's last cursor. What must be true of the cursor for that to be safe?

Decide which facts an invoice line copies instead of joining

Medium · denormalisation · immutable records · foreign keys · rounding

invoice_line_item already denormalises tenant_id, which is reachable through invoice_id, and stores amount_minor even though quantity times unit_price_micros would recompute it. A reviewer asks you to normalise both away, and separately asks whether the tenant's legal name and billing address should be copied onto the invoice header. Decide each case. For every field you keep denormalised, name the read pattern or the invariant that justifies it, the anomaly the copy can develop, and the mechanism that prevents that anomaly here.

Approach

  1. Split the question into two kinds of copy, because they fail differently. A copy of a currently mutable fact is a cache: it drifts and needs invalidation. A copy of a fact frozen at write time is not a cache at all, it is the record of what happened, and normalising it away destroys information the source no longer holds.
  2. Keep tenant_id on the line. It costs 8 bytes, it leads every index on the table so no read is ever accidentally cross-tenant, and it turns a wrong join into an empty result rather than another tenant's money. Prevent the drift structurally: a unique constraint on invoice (invoice_id, tenant_id) plus a composite foreign key from the line on (invoice_id, tenant_id) makes a mismatched pair impossible, so the database enforces agreement instead of a code review.
  3. Keep amount_minor. Rounding must happen exactly once, at a named site, with a stated mode (half-even here). If readers recompute from quantity and unit_price_micros, every reader owns a rounding decision, and half-up and half-even diverge systematically across thousands of lines rather than cancelling out. A check constraint can bound the stored value but deliberately cannot re-derive it.
  4. Copy the legal name and billing address onto the invoice header, written once and never updated. The statement must show what was true when it was sealed, and the tenant record will change afterwards. This is a snapshot for the same reason source_rollup_watermark is stored per line: without it, nobody can reconstruct what the customer was told.
  5. Name the read pattern that pays for all of it. Rendering, dispute response and export are per-tenant, per-period reads over thousands of lines that would otherwise join back to slowly changing dimensions that no longer hold the historical value. The write side is a once-per-period batch, so the extra columns cost nothing that matters.
  6. Concede the case where the reviewer is right: a mutable operational attribute such as the tenant's current plan name has no business on a line. If a report wants it, join. If a statement needs the plan as of the period, that is another snapshot and it belongs on the header with the rest.

Follow-up

  • Write the composite foreign key and the unique constraint it requires on the parent. What does it cost on every line insert, and what does it do to a bulk load?
  • A tenant is renamed after being invoiced. Which rows change, and what does the customer see on last quarter's PDF?
  • Where does currency live, and what breaks if a tenant's billing currency changes between two periods?

Describe your approach to designing a high-availability microservices architecture.

Medium · system design and architecture

Approach

  1. Choose a partition key and say what query it makes expensive.
  2. Fix the scope first: who calls this, how often, and what they do when it fails.
  3. State the consistency you need, and where you are willing to be stale.

Follow-up

  • How does this behave when that dependency is down for an hour?
  • What breaks first when traffic grows ten times?

How do you ensure consistency in a distributed system during a network partition?

Medium · system design and architecture

Approach

  1. Choose a partition key and say what query it makes expensive.
  2. Name the read and write paths separately; they rarely have the same bottleneck.
  3. Fix the scope first: who calls this, how often, and what they do when it fails.

Follow-up

  • What would you drop to keep the system up under load?
  • How does this behave when that dependency is down for an hour?

Webhook fan-out with per-endpoint isolation and backoff

Medium · fan-out · backpressure · circuit breaker · ordering

One domain event fans out to every matching subscription, producing a webhook_delivery row per (subscription_id, event_id, redelivery_seq). Peak unique event rate is 20k/second; attempts run five to ten times that once fan-out and retries are counted. One customer endpoint has returned 503 for six hours and its backlog holds days of events; every other customer must be unaffected. Design the delivery system: how a worker claims work, the backoff schedule, the per-endpoint circuit breaker, the queue partitioning, and whether you offer ordering per subscription. State the delivery guarantee in one sentence.

Approach

  1. State the guarantee first, because it determines the rest: at-least-once with a stable event_id, and the consumer documented as responsible for idempotency. Exactly-once over HTTP is not deliverable - the 200 can be lost after the customer has already committed - so any design that promises it is either lying or is really offering at-most-once.
  2. Partition work per subscription rather than into one global pool, with a concurrency cap per subscription. With a shared pool, the endpoint that has been dead for six hours consumes workers on retries that will fail, and every other customer's delivery latency rises: head-of-line blocking across tenants is the exact failure being designed against here.
  3. Claim by compare-and-set with a fencing token: UPDATE webhook_delivery SET status = 'in_flight', lease_token = $new, leased_until = now() + interval '60 seconds' WHERE delivery_id = $1 AND status IN ('pending','failed_retryable') AND (leased_until IS NULL OR leased_until < now()), and make the terminal write carry AND lease_token = $new so a paused worker's late write is rejected rather than overwriting a newer attempt. Find due work through the partial index on next_attempt_at WHERE status IN ('pending','failed_retryable'), so the scan is proportional to live rows rather than to the terminal rows that outnumber them by orders of magnitude.
  4. Use full jitter: sleep uniformly in [0, min(cap, base x 2^(attempt-1))]. Plain exponential backoff hands a recovering endpoint its entire backlog as one synchronised herd and knocks it over again; full jitter de-correlates it. Then check the schedule actually spans the retention you promise - with base 1 s and a 3,600 s cap, twenty attempts have an expected total elapsed time of only about 4.6 hours, so a twenty-four-hour promise needs roughly fifty-nine attempts or a larger cap.
  5. Trip a circuit per endpoint on consecutive failures or a failure ratio over a rolling window: stop dispatching, push next_attempt_at out or mark new deliveries dropped_circuit_open, and half-open with exactly one probe rather than a batch. Bound the backlog explicitly with a per-subscription cap or retention, and decide in advance whether a recovered endpoint receives six hours of events at full rate or a pointer telling it to fetch what it missed.
  6. Offer ordering only as an opt-in mode of one in-flight attempt per subscription, and price it honestly: with parallel attempts a retried event overtakes a newer one, so ordering requires serialisation, and serialisation means one slow endpoint blocks its own queue entirely. That converts a shared problem into that customer's own problem, which is the right place for it, but it is still a real cost.

Worked solution (35 min)

  1. Compute the attempt rate: 20k unique events/second x mean fan-out x retry multiplier, and size worker pools and the per-subscription concurrency cap from it.
  2. Write the claim statement and the terminal write, and point at the clause that rejects a resumed worker's stale write.
  3. Tabulate the backoff for attempts 1 to 20 with base 1 s and cap 3,600 s, take the expected value of each full-jitter sleep as half its ceiling, and sum to get total expected elapsed coverage.
  4. Decide the policy for a subscription down six hours: events buffered, bytes held, and what the customer actually receives when it returns.

Expected result: At-least-once with a stable event_id; per-subscription lanes with a concurrency cap; lease-and-fence claiming; full jitter whose schedule matches the retention promised - with base 1 s and a one-hour cap, twenty attempts covers only about 4.6 hours of expected elapsed time, so twenty-four hours needs roughly fifty-nine attempts or a larger cap; a per-endpoint breaker with a single half-open probe; ordering offered only as opt-in single-in-flight with head-of-line blocking named as its price.

Verify it yourself

  • Sum the expected sleeps in your schedule and compare against the retention window you promised the customer. If the two numbers disagree, one of them is wrong and it is usually the promise.
  • Execute the terminal write with a stale lease_token and confirm it affects zero rows. If it succeeds, the lease was doing the work alone and the token is decorative.
  • The dead endpoint's backlog must not be visible in any queue another subscription's workers poll. If one index scan serves all subscriptions, the isolation is nominal.

Follow-up

  • The endpoint recovers. Does it receive six hours of events at full rate, and what does that do to it?
  • Trace the exact code path by which an event belonging to one tenant could be signed and sent to another tenant's endpoint.
  • A customer insists they never received an event your row marks delivered. What evidence do you have, and what does payload_digest let you prove?

Hourly rollups merge one hour and lose another

Easy · timezone · rollups · reconciliation

Reconciliation flags one tenant on one day. Summing usage_event.quantity by hour of occurred_at gives 24 non-empty hours, but usage_rollup_hourly holds 23 rows for that tenant, workspace and SKU, one of which carries roughly the sum of two adjacent hours. Other days reconcile exactly, and the affected date matches a civil-time transition. hour_start is documented as truncated to the hour in UTC. You have both tables, the rollup job source, and its runtime environment. Give an ordered checklist, the mechanism, and the correction path for a day that may already be sealed.

Approach

  1. Bisect by dimension until one cell explains the whole difference: tenant, then day, then SKU, then hour. A defect confined to a single transition date already rules out deduplication and late arrival, both of which are indifferent to which hour an event lands in.
  2. Read the truncation with its precondition stated: date_trunc on a timestamptz value is evaluated in the session TimeZone, not in UTC. If the job connects without pinning that setting, it inherits the server or container default.
  3. Follow that to the collision: in a zone that observes daylight saving, two distinct UTC hours map to the same local wall-clock label at the autumn transition, so both fold into one key under the unique constraint on (tenant_id, workspace_id, sku, hour_start) and their quantities sum into one row. At the spring transition a label never occurs and the row is simply absent.
  4. Confirm from data rather than from reading code: run the same aggregate twice, once with the session pinned to UTC and once with the job host zone, and check that the second reproduces the stored rollup exactly.
  5. Fix at the source by pinning the connection to UTC explicitly, or by truncating on occurred_at AT TIME ZONE 'UTC', rather than relying on a default that differs between a developer machine, CI and production.
  6. Correct according to status, not convenience: an open hour is recomputed with revision incremented, a sealed hour is frozen and the difference becomes an adjustment line on the next invoice with voided_by_line_id pointing at the line it reverses.

Follow-up

  • The same job also emits a daily figure for a dashboard. Why can a correct hourly rollup still produce a wrong day, and what does the tenant's billing timezone have to do with it?
  • How would you detect this class automatically rather than waiting for reconciliation, given that it only manifests twice a year per zone?

Suggested practice checklist

Four days sample coding, design, fundamentals and the practical rounds at deliberately shallow depth, which is enough to surface the topics you did not know were in scope. That map, rather than a guess made on day one, decides where the last three days go.

Day 1 — Coding, one pass at shallow depth

  • Solve one problem from each of six families, an array with two pointers, hash counting, binary search, a tree traversal, a graph traversal and one dynamic program, under a hard twenty-minute cap with no extensions, marking each finished, late, or stalled.
  • For every stall, write the exact move you could not make rather than the subject, so the note reads could not turn the recurrence into a loop rather than bad at dynamic programming.
  • Fix nothing today. The value of the pass is the unfixed record.

Deliverable: Six timed attempts marked finished, late or stalled, each stall carrying a named blocking move.

Day 2 — Design, one pass at shallow depth

  • Spend twenty minutes each on three different shapes, a read-heavy feed, a write-heavy ingest path, and something needing a transaction across two entities, stopping each at requirements, interface and data model.
  • After each, write the first question you could not answer, which is usually a number you could not estimate or a failure mode you had no vocabulary for.
  • Mark which of the three you would be most relieved not to be asked, and treat that as data rather than as a preference.

Deliverable: Three shallow designs, each with the first unanswerable question written at the bottom.

Day 3 — Fundamentals and the practical rounds

  • Answer eight short questions in writing at four minutes each, covering the material that fills the gaps between the big rounds: what happens between a URL and a rendered page, what an index costs on write, when a process is preferable to a thread, and what conditions a deadlock requires.
  • Do one thirty-minute practical task of the kind a take-home compresses: read an unfamiliar two-hundred-line file and write what it does, what you would change, and the one thing you remain unsure of.
  • Score every answer fluent, correct but slow, or absent, and keep the absent ones visible.

Deliverable: Eight scored short answers and one written reading of unfamiliar code.

Day 4 — The rounds that are about you, and the map

  • Deliver three behavioural answers aloud against a timer, a conflict, a failure you owned, and a decision made without enough information, marking any that ran past three minutes or contained no number.
  • Assemble the map: every marked item from days one to three on a single page, sorted by how likely it is to appear in your loop rather than by how uncomfortable it felt.
  • Choose exactly two areas for the remaining three days and write down what you are deliberately abandoning.

Deliverable: A one-page scored map of the whole surface area with two areas chosen and the rest explicitly abandoned.

Day 5 — First chosen area, to the depth you skipped

  • Work the higher-ranked area in four focused blocks, choosing items one level above where you stalled rather than repeating what already works.
  • After each block write the rule you extracted in one sentence with its precondition attached, since a rule carrying no precondition is exactly what fails under a variation.
  • Re-attempt the day-one or day-two item that exposed this area and compare against the original timing.

Deliverable: Four worked blocks, a timed re-attempt against the original, and three one-sentence rules with preconditions.

Day 6 — Second chosen area, where the gap is coverage rather than speed

  • Treat the second area differently from the first. Day five drilled something you could already half-do; this one is usually a topic you had simply never met, so build one worked reference example end to end and keep it, rather than attempting six problems badly.
  • Write down the vocabulary you were missing on day two or three, five terms at most, each with the one sentence that makes it usable in an answer rather than the textbook definition.
  • Redo the shallow attempt that exposed this area and note whether you now fail later in the problem, because moving the failure point is the realistic gain from a single day and is worth more than a score that did not change.

Deliverable: One worked reference example for the newly covered area, a five-term vocabulary list, and a note on where the failure point moved.

Day 7 — Reassemble the loop

  • Sit two rounds back to back with no gap, ordering them so the area you chose second comes last, because the map was built from rested, isolated attempts and the loop will reach your weaker area when you are already spent.
  • Write where the second round suffered from the first, which is normally the point at which structure collapses into narration.
  • Reduce the week to one page holding only the rules you can state without reading them.

Deliverable: Mock notes on cross-round carryover plus a one-page card of rules you can recite from memory.

Review and mentoring: what you let through

Counting review comments or mentees proves nothing. The useful version is a specific change you approved with a reservation you stated, or one you blocked and the delay that cost. Say which standard you were holding and why it was worth the friction. A mentoring story needs the thing the other person can now do without you.

Unblock an engineer on a job run that finished twice

Easy · mentoring · fencing tokens · lease expiry · debugging method

An engineer two weeks into the team brings you a job_run row showing status succeeded with an exit_code written by a worker declared dead ten minutes earlier; the retry attempt also shows succeeded. They have spent a day adding logging and are no closer. You have twenty minutes and you do not want to take the keyboard. Describe how you unblock someone: the question you ask first, what you let them find themselves, the concept you name and when, and how you check the next day that they own the fix rather than having watched you produce it.

Approach

  1. Ask what they expect rather than what they see: which statement set status to succeeded, and what did it check before writing? That question points directly at the update's WHERE clause, which is where the answer lives, and it costs them nothing to answer, so it does not read as a test.
  2. Let them build the timeline themselves from the row: queued_at, started_at, leased_until, finished_at and worker_id, on both the original run and the retry. Two different worker_ids with a lease expiry between them tells the whole story, and they will see it before you say it.
  3. Name the concept once the evidence has earned it. A lease bounds time; it does not prevent a write. The store has to reject a stale writer, which means the update carries a fencing token the row compares — update job_run set status = 'succeeded' where run_id = $1 and lease_token = $2 and status = 'running' — and a long garbage-collection pause or a brief partition is enough to produce what they are looking at.
  4. Point at the second, less obvious half and let them decide it: 'lost' exists in the status enum precisely so a run whose worker vanished is not recorded as failed, because failed asserts an outcome nobody observed and the system then bills and retries on that assertion. Ask them what these two rows should have said.
  5. Leave them with the next step rather than the patch — a test that kills the first worker after the sandbox exits and before the row is written — and say when you are available again, so the offer is real rather than polite.
  6. Check ownership the next day by what they produced, not by asking if it went well: a test that reproduces the window proves they understood it; a test that only asserts the new WHERE clause proves they copied it. Ask them to explain it to a third person and listen for whether the explanation is theirs.

Follow-up

  • They propose a longer lease instead of a token. What do you say, and what breaks when legitimate runs last thirty minutes?
  • How can you tell whether your explanation landed or they simply deferred to you?
  • The same engineer hits a variant of this next month. What did you fail to teach the first time?

Estimate a tenant-leading index migration you have never run

Hard · estimation · online migration · index builds · uncertainty

Someone needs a date. usage_event carries an index on (occurred_at) and needs (tenant_id, occurred_at); the largest tenant holds roughly a hundred times the median tenant's rows, the table is partitioned daily with years of retention, and you have never run a migration on a table this large. Give an estimate you would defend: how you decompose the work, the two or three numbers you would go and measure first, the range and confidence you state, and what you commit to when the person asking needs a single date today.

Approach

  1. Refuse the bare number and then give one anyway, in the form that is actually useful: a range plus the measurement that collapses it. 'Four to eleven days; one afternoon building this index on a restored copy of the largest partition takes that to within a day' is an answer, while 'it depends' is not.
  2. Decompose by failure mode rather than into equal chunks, because that is where estimates go wrong. On a partitioned parent you create the index ON ONLY the parent, build each partition's index with CREATE INDEX CONCURRENTLY, then ALTER INDEX ... ATTACH PARTITION, at which point the parent index becomes valid. CONCURRENTLY does not block writes but scans each partition twice, waits out older transactions, cannot run inside a transaction block, and on failure leaves an invalid index you must drop concurrently and retry.
  3. Name the two unknowns that dominate and price them: build time on one restored partition of realistic size, and whether the planner actually chooses the new index for the skewed tenant, since selectivity for a tenant holding most of the rows is a different question from selectivity for the median tenant. Both are half-day measurements against a replica, and both are cheaper than being wrong by a week.
  4. State the assumptions the range is conditional on, because that is what makes a slip a re-estimate instead of a credibility event: no partition above a stated row count, one concurrent build at a time so it does not compete with ingest for I/O, and an ingest backlog that can absorb the added write amplification while both indexes exist.
  5. Budget the step nobody budgets: verification and the old index's removal. Dropping the old index is fast, but deciding it is safe to drop means confirming no plan still uses it, and that confirmation waits on real traffic across a full weekly cycle rather than on your patience.
  6. Answer the single-date request honestly. Commit to a date for the first checkpoint — the measured build number from the replica — and to re-estimating on that date, and say plainly what you are not committing to yet. A date with a scheduled re-estimate is worth more to the asker than a confident wrong one, and you should say why in those words.

Follow-up

  • The concurrent build fails half way through the largest partition. What is the state of the database and what do you do next?
  • Your estimate slips by sixty percent. Which assumption broke, and at what point would you have known?
  • The person asking needs the date for a customer commitment. Does your answer change?

Own the incident where invoices undercounted metered usage

Medium · incident response · at-least-once · billing correction · postmortem

A metering consumer acknowledged each batch before committing the fold into usage_rollup_hourly. A rolling deploy restarted consumers mid-batch for two hours; roughly 1.4M usage_event rows were acknowledged and never folded, and 61 invoices sealed against the resulting rollups before anyone noticed. Take the owner's role. Describe an incident of comparable blast radius you owned: how it surfaced, the query that sized the loss, what you stopped first, and how the money was corrected. Give a wall-clock timeline and one thing you got wrong while it was still live.

Approach

  1. Open with the invariant that broke and the direction of the error, because they determine everything else: acknowledging before committing makes the consumer at-most-once, so this loses events rather than duplicating them, and loss raises no error anywhere. A listener who hears 'we lost revenue silently' knows immediately why detection took two hours.
  2. Size it with a stated reconciliation rather than an adjective: sum(quantity) from usage_event grouped by (tenant_id, sku, hour of occurred_at) over the window, against usage_rollup_hourly.quantity_sum on the same keys, filtered to environment='production' because staging and sandbox are metered but not billed. Then bisect by hour and tenant until single cells explain the gap. Say how long that ran and whether a replica could serve it while the incident was live.
  3. Separate mitigation from fix and say which came first. Mitigation is holding the sealing job, because a sealed row is frozen by design and every minute of sealing converts a recoverable rollup into an invoice correction. The fix is moving the acknowledgement after the commit, which re-introduces duplicates that the dedup check on (tenant_id, idempotency_key) must now absorb.
  4. State the correction path in the domain's own terms: sealed periods are never edited, so each affected tenant gets an adjustment line on the next invoice with kind='adjustment' and voided_by_line_id pointing at the line it reverses, priced against the same rate tier and carrying the watermark it priced against. That is four separate numbers — tenants affected, minor units, the cycle the adjustment lands in, and when customers were told.
  5. Close on one prevention control with its cost, not five: a per-hour reconciliation comparing raw sum to rollup sum that pages above a threshold. Name the threshold and the false-page rate you accepted, because a detector nobody will keep staffed is not prevention.
  6. Name a mistake you made inside the response window — the wrong first hypothesis, a mitigation that made it worse — rather than a design mistake from six months earlier. That is the part candidates rehearse away and interviewers weight heavily.

Follow-up

  • Your fix moves the acknowledgement after the commit. What breaks now, and what absorbs it?
  • One undercharged tenant has since churned. Do you bill them, and who decides?
  • How would you have caught this in ten minutes instead of two hours, and what would that detector cost you in pages per week?